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1 answer:
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Answer:
Step-by-step explanation:
Standard form of a sideways parabola:
Given equation:
Add x to both sides:
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<u>Standard form of circle equation</u>
(where (a,b) is the center and r is the radius)
Given equation:
Group like terms:
Divide by 2:
Factor by completing the square for each variable:
Rearrange into standard form:
Therefore, the circle has a center at (4.5, 2.5) and a radius of √23
Answer:
Step-by-step explanation:
we have
----> The degree of this polynomial is 1 (linear equation)
Remember that
The zero of the polynomial is the value of x when the value of f(x) is zero
so
For f(x)=0
solve for x
----> the zero of the polynomial or x-intercept
see the picture attached to better understand the problem
we know that
two tangent segments drawn from the same exterior point are congruent
so
JA=JB ,
LA=LC,
KC=KB
JA=13 units
LA=7 units
kC=10 units
hence
perimeter = JA+JB+LA+LC+KC+KB------> 13+13+7+7+10+10------> =60 units
therefore
the answer is
the perimeter of triangle JKL is 60 units
