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Stells [14]
3 years ago
8

MANY POINTS! please answer questions 5,6,7

Mathematics
1 answer:
Maslowich3 years ago
5 0

Answer:

Question 5

8\sqrt{5} + 3\sqrt{30}

Question 6

yes

Question 7

no

Step-by-step explanation:

Question 5

\sqrt{5} (8*3\sqrt{6})\\8\sqrt{5} + 3\sqrt{5*6}\\8\sqrt{5} + 3\sqrt{30}

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The profile of the cables on a suspension bridge may be modeled by a parabola. The central span of the bridge is 1210 m long and
brilliants [131]

Answer:

The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

Step-by-step explanation:

The equation of the parabola is:

y=0.00035x^{2}

Compute the first order derivative of <em>y</em> as follows:

 y=0.00035x^{2}

\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]

    =2\cdot 0.00035x\\\\=0.0007x

Now, it is provided that |<em>x </em>| ≤ 605.

⇒ -605 ≤ <em>x</em> ≤ 605

Compute the arc length as follows:

\text{Arc Length}=\int\limits^{x}_{-x} {1+(\frac{\text{dy}}{\text{dx}})^{2}} \, dx

                  =\int\limits^{605}_{-605} {\sqrt{1+(0.0007x)^{2}}} \, dx \\\\={\displaystyle\int\limits^{605}_{-605}}\sqrt{\dfrac{49x^2}{100000000}+1}\,\mathrm{d}x\\\\={\dfrac{1}{10000}}}{\displaystyle\int\limits^{605}_{-605}}\sqrt{49x^2+100000000}\,\mathrm{d}x\\\\

Now, let

x=\dfrac{10000\tan\left(u\right)}{7}\\\\\Rightarrow u=\arctan\left(\dfrac{7x}{10000}\right)\\\\\Rightarrow \mathrm{d}x=\dfrac{10000\sec^2\left(u\right)}{7}\,\mathrm{d}u

\int dx={\displaystyle\int\limits}\dfrac{10000\sec^2\left(u\right)\sqrt{100000000\tan^2\left(u\right)+100000000}}{7}\,\mathrm{d}u

                  ={\dfrac{100000000}{7}}}{\displaystyle\int}\sec^3\left(u\right)\,\mathrm{d}u\\\\=\dfrac{50000000\ln\left(\tan\left(u\right)+\sec\left(u\right)\right)}{7}+\dfrac{50000000\sec\left(u\right)\tan\left(u\right)}{7}\\\\=\dfrac{50000000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+5000x\sqrt{\dfrac{49x^2}{100000000}+1}

Plug in the solved integrals in Arc Length and solve as follows:

\text{Arc Length}=\dfrac{5000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+\dfrac{x\sqrt{\frac{49x^2}{100000000}+1}}{2}|_{limits^{605}_{-605}}\\\\

                  =1245.253707795227\\\\\approx 1245.25

Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

7 0
3 years ago
The Green Goober, a wildly unpopular superhero, mixes 3 liters of yellow paint with 5 liters of blue paint to make 8 liters of s
Degger [83]

Let

y------> the amounts (in liters) of yellow paint

b-----> the amounts (in liters) of blue paint

we know that

\frac{y}{b}=\frac{3}{5}

so

y=\frac{3}{5}b

therefore

<u>the answer is</u>

y=\frac{3}{5}b

5 0
3 years ago
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Find the area of the triangle by forming a parallelogram.<br> Please I need it fast!
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Answer:

14

Step-by-step explanation:

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Polygon ABCD has the following vertices:
yKpoI14uk [10]

9514 1404 393

Answer:

  (b)  38.5

Step-by-step explanation:

The polygon is a trapezoid with bases 4 and 7 and height 7. Its area is given by the formula ...

  A = (1/2)(b1 +b2)h

  A = (1/2)(4 +7)(7) = 77/2

  A = 38.5 . . . . square units

8 0
3 years ago
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