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Tom [10]
3 years ago
10

Selena's favorite basketball player is 6 feet 8 inches tall how tall is Selena's favorite basketball player

Mathematics
2 answers:
iris [78.8K]3 years ago
8 0

Answer:

6ft 8 inches or 80 inches

Step-by-step explanation:

What you are asking is already given to you.

pav-90 [236]3 years ago
6 0

Answer:

6 feet 8 inches

Step-by-step explanation:

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Cut 9ft piece into 12inch & Every cut remove 1/8 inch
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So each foot is 12 inches so to remove 8 feet to get 12 in you need to remove 8 times 12 inches total or 96 in and each cut removes 1/8 in so times 96 by 8 and get 768 total cuts
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Tisha babysat for 5 hours and earned $32.50. At the same rate, how much would she earn in 8 hours?
kolezko [41]
Start by finding her hourly rate. 32.50/5 = 6.5
Next times 6.5 * 8 = 52
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Write a rule for each sequence. Find the next three terms.<br><br> 8,14,20,26
anastassius [24]
Aruthmetic sequene is
an=a1+(n-1)d
where d=common difference between terms
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a1=8
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8+6n-6
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8 0
3 years ago
A standard deck of playing cards has 52 cards total that contains 13 of each suit (hearts, diamonds, clubs and spades). What is
schepotkina [342]

Answer:

C 1/2

Step-by-step explanation:

There are 4 suits, 2 suits are  red (hearts and diamonds) while 2 are black (clubs and spades)

Since 13 cards are in each suit, 26 cards are red ( 2 * 13)  

There are 52 total cards

P (red) = red cards/ total cards

           = 26 / 52

           = 1/2

8 0
3 years ago
A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch
ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

P = a person passes the security system

H = a person is a security hazard

Given:

P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01

Then,

P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The value of P (P) is:

P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0
3 years ago
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