A^2-3a+14 is the answer :)
Answer:
m<FAB = 75°
m<BAC = 105°
Step-by-step explanation:
First, find the value of x.
(13x - 3)° = (3x + 2)° + 55° (exterior angle theorem of a ∆)
Solve for x
13x - 3 = 3x + 2 + 55
13x - 3 = 3x + 57
Collect like terms
13x - 3x = 57 + 3
10x = 60
Divide both sides by 10
x = 6
✔️m<FAB = 13x - 3
Plug in the value of x
m<FAB = 13(6) - 3 = 78 - 3
m<FAB = 75°
✔️m<BAC = 180 - m<FAB (angles on a straight line/supplementary angles)
m<BAC = 180 - 75 (substitution)
m<BAC = 105°
Answer:
x =68
Step-by-step explanation:
The sum of the angles of a triangle are 180
37+75+x = 180
Combine like terms
112+x = 180
Subtract 112 from each side
112+x-112=180-112
x =68
First, find the slope of the initial line;
m=(y₁-y₂)/(x₁-x₂)
m=(4-0)/(11-8)
m=4/3
If two lines are parallel, the slope is the same although the intercept can differ.
If this parallel lines passes through the point (4, 5);
y=(4/3)x+c <-- plug in coordinates to solve for c
5=(4/3)(4)+c
(15/3)=16/3+c
(15/3)-(16/3)=c
-1/3=c
Therefore, the final equation should be y=4/3x-1/3
Hope I Helped :)
