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3 years ago

9

(3^2 +4) -6+4= {^ means power to...}

1 answer:

Misha Larkins [42]3 years ago

4 0

The awnser is 11
1. 3*3=9
2. 9+4=13
3. 13-6=7
4. 7+4=11

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Solve the following quadratic equation by the square root method. (Y-9)^2=64

enot [183]

Hello!

To solve this, first perform the opposite operation for the last operation (on the left side) on both sides. The last operation of the left side is squaring. Therefore, square root both sides.

$(y - 9)^{2} = 64$

$y - 9 = ±\sqrt{64}$

$y - 9 = ±8$

Please note that you must include ±. This is because the square root of 64 can be either positive or negative, as a square of either a positive or negative number is positive.

Now, add 9 to both sides.

$y = 9±8$

There are 2 solutions from here. One comes from adding 8, and the other subtracting 8. Therefore, the two solutions are:

y = 9 + 8 = 17

y = 9 - 8 = 1

Therefore, your two solutions are 17 and 1.

Hope this helps!

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3 years ago

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Grace [21]

Answer:

an = 1/2 (n) (n+1)

Step-by-step explanation:

1,3,6,10,.........

3-1=2

6-3=3

Each term is different so there is no common difference. It is not an arithmetic sequence

3/1=3

6/3 =2

Each term is different so there is no common ratio. It is not a geometric sequence

1 3 6 10

+2 +3 +4

a1 = 1

a2 = 3

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3 years ago

A boat is pulled toward a dock by means of a rope wound on a drum that is located 6 ft above the bow of the boat. If the rope is

Monica [59]

Answer:

Step-by-step explanation:

Given that:

The height of the dock (h) = 6

Let represent d to be the distance between the boat and the dock

Let the length of the rope between the boat and the drum be denoted by (l)

Then, the rate of change for the length of the rope be:

dl/dt = -5 ft/s

Using Pythagoras rule to determine the relationship between these values, we have:

$l^2 = h^2 +d^2$

$l^2 = 6^2 + d^2$

$l^2 = 36 + d^2$

We relate to: $2l * \dfrac{dl}{dt} = 2d* \dfrac{dd}{dt}$

From the question;

l = 34,

So to find $\dfrac{dd}{dt}$ , we get;

$d = \sqrt{l^2 - 36}$

$d = \sqrt{34^2 - 36}$

$d = \sqrt{1156- 36}$

$d = \sqrt{1120}$

d = 33.46

So, we have:

$\dfrac{dd}{dt}= \dfrac{l}{d} \times \dfrac{dl}{dt}$

$\dfrac{dd}{dt}= \dfrac{34}{33.46} \times - 5$

$\dfrac{dd}{dt}= 1.016 \times - 5$

$\dfrac{dd}{dt}=-5.08 \ ft/sec$

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