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viktelen [127]
4 years ago
13

Write the set of points greater than or equal to −5−5 but strictly less than 44, excluding 00, as a union of two intervals (if y

ou're having trouble with this, try drawing a number line):
Mathematics
1 answer:
Alecsey [184]4 years ago
7 0
What we want to draw is the half closed interval:

                                          I=   [-5, 4) excluding 0,

as the union of 2 different intervals say a and b.

Let a be the interval containing the smallest value.

Then the smallest value of a is -5, and the largest possible value of a is 0, not included, if we want to write a as an interval, without "gaps", or "holes".

So a=[-5, 0)

similarly, b=(0, 4).


Answer: [-5, 4)=[-5, 0)∪(0, 4)

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the graph shows the location of a bank in a library each Square on the graph represents one block which path can be taken to go
Nookie1986 [14]

Answer:

Step-by-step explanation:

The answer is 5blocks to the right and 3 blocks up thank me LATER

5 0
3 years ago
What are the roots of the polynomial equation x^3-5x+5=2x^2-5? Use a graphing calculator and a system of equations. Round nonint
leonid [27]

The right answer is c. –2.24, 2, 2.24


This question needs to be solved in two ways. First, using a graphing calculator. Next, using a system of equations.


1. Using a graphing calculator.


We have the following polynomial equation:

x^3-5x+5=2x^2-5


By ordering this equation we have:

x^3-2x^2-5x+10=0


So, we can say that this equation comes from a function given by:

f(x)=x^3-2x^2-5x+10


Thus, by plotting this function, we have that the graph of this function is indicated in Figure 1. By zooming, we can see, in Figure 2, that the roots of the polynomial equation are the x-intercepts of f(x) which are:


x_{1}=-2.236 \\ \\ x_{2}=2 \\ \\ x_{3}=2.236


Finally, rounding noninteger roots to the nearest hundredth we have:


\boxed{Root_{1}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=2.24}


2. Using a system of equations.


The ordered equation is:

x^3-2x^2-5x+10=0


By arranging to factor out we have:

x^3-5x-2x^2+10=0


Then, by factoring:

x(x^2-5)-2(x^2-5)=0


Term (x^2-5) is a common factor, thus:


(x-2)(x^2-5)=0 \\ \\ (x-2)(x-\sqrt{5})(x+\sqrt{5})=0 \\ \\ Finally: \\ \\ \boxed{Root_{1}=-\sqrt{5}=-2.24} \\ \\ \boxed{Root_{2}=2} \\ \\ \boxed{Root_{3}=\sqrt{5}=2.24}

6 0
3 years ago
Read 2 more answers
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MatroZZZ [7]
S represents the best distance from 1 and 0 to represent 33 1/3%
3 0
3 years ago
Read 2 more answers
There are 3 red marbles in a bag of 12 marbles. A larger bag has a total of 26 marbles, including 7 red marbles. Are the chances
qwelly [4]
Short answer: No

Explanation: if you bring the fractions down as low as possible, the first bag has a 1 in 4 chance of getting a red marble. The 2nd bag can't be brought down anymore because 26 and 7 do not share any common divisors.
8 0
3 years ago
In a particular country, there are two types of currency: Kabuls and Carumpts. 8 Kabuls and 2 Carumpts are worth $61.70. 3 Kabul
Misha Larkins [42]

Answer:

Kabuls = 7.5

Carumpts= 0.85

Step-by-step explanation:

Let x represent the price of kabuls

Let y represent the price of carumpts

8x + 2y= 61.70......equation 1

3x + 10y= 31.........equation 2

Multiply equation 1 by 3 and equation 2 by 8

24x + 6y= 185.1

24x + 80y= 248

-74y = -62.9

y= 62.9/74

y= 0.85

Substitute 0.85 for y in equation 1

8x + 2(0.85) = 61.70

8x + 1.7= 61.70

8x = 61.70-1.7

8x = 60

x= 60/8

x= 7.5

Hence the dollar value for kabuls is 7.5 and carumpts is 0.85

3 0
3 years ago
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