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DaniilM [7]
2 years ago
6

Leave answer in the simplest radical form.

Mathematics
1 answer:
slega [8]2 years ago
7 0

\cfrac{7x^{-\frac{3}{2}} ~~ y^{\frac{5}{2}} ~~ z^{-\frac{2}{3}}}{56 x^{-\frac{1}{2}} ~~ y^{\frac{1}{4}}}\implies \cfrac{7}{56}\cdot \cfrac{y^{\frac{5}{2}} ~~ y^{-\frac{1}{4}}}{x^{-\frac{1}{2}} ~~ x^{\frac{3}{2}} ~~ z^{\frac{2}{3}}}\implies \cfrac{1}{8}\cfrac{y^{\frac{5}{2}-\frac{1}{4}}}{x^{-\frac{1}{2}+\frac{3}{2}}~~ z^{\frac{2}{3}}}

\cfrac{y^{\frac{9}{4}}}{8x z^{\frac{2}{3}}}\implies \cfrac{\sqrt[4]{y^9}}{8x\sqrt[3]{z^2}}\implies \cfrac{\sqrt[4]{y (y^2)^4}}{8x\sqrt[3]{z^2}}\implies \cfrac{y^2 \sqrt[4]{y}}{8x\sqrt[3]{z^2}}

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Scrat [10]
42 because x is equal to its corresponding side
7 0
3 years ago
The point (-3,-1) is the midpoint of (x,y) and (5,4). Find the point (x,y).
nirvana33 [79]

Answer:

(-11, -6)

Step-by-step explanation:

Find the distance between the midpoint, (-3, -1) and (5, 4). This can be calculated by finding the difference between the x coordinates and y coordinates.

-3 - 5 = -8 (distance between x coordinates)

-1 - 4 = -5 (distance between y coordinates)

Find the point (x, y) by subtracting 8 from the midpoint's x value, and then subtracting 5 from the midpoint's y value.

-3 - 8 = -11

-1 - 5 = -6

So, the point (x, y) is (-11, -6)

4 0
2 years ago
Shaka and ajani playa a game shaka scores 30%of maximum points and misses the record by 15 points ajani gets 40% of maximum pint
stellarik [79]

Step-by-step explanation:

First, we should focus on their records and percents.

Shaka: 30%, -15 points.

Ajani: 40% +35 points.

When we subtract 35 and -15, we get the difference of 50.

We know 10% is 50 point difference, 20% is 100 point difference, 30% is 150 point difference, etc.

But that's not correct.

  • It has to be in the Negatives.
  • It cannot be positive under 30%.

Since 30% is -15 points, we subtract 50 for 20%, then another 50 for 10%.

Our Correct work is:

0% = -0, 10% = -115, 20% = -65, (30% = -15, 40% = 35.)

- We are correct.

Then, since we are correct, we keep going.

30% = -15, 40% = 35, 50% = 85, 60% = 135, 70% = 185, 80% = 235, 90% = 285, 100% (Or Maximum Point): 335.

Therefore, the Maximum Point is 335 points.

Best of Luck to you!

If you have any questions, feel free to comment below.

Merry Christmas and have a Happy New Year!

Thank You!

Read more on Brainly.com - brainly.com/question/14270303#readmore

5 0
3 years ago
Simplify sin x / CSC x + cos x / sec x​
Artyom0805 [142]
  • sinx/cscx =sinx x sinx =sin^2x
  • cosx/secx=cosx x cosx=cos^2x
  • sin^2x+cos^2x=1 "trigonometric identity"
8 0
3 years ago
Use the given data to construct a box plot and identify the 5-number summary. Eleven different second-year medical students at B
Galina-37 [17]

Answer:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

Step-by-step explanation:

We have the following data given:

130, 135, 140, 120, 130, 130, 144, 143, 140, 130, 150

If we sort the values on increasing order we got:

120 130 130 130 130 135 140 140 143 144 150

The minimum and maximum are:

Min =120, Max= 150

The first quartile can be calculated with this data:

130, 135, 140, 120, 130, 130

And the middle value is:

Q_1 = \frac{140+120}{2}=130

The median is the value in the 6th position from the dataset ordered and we got:

Median= 135

The third quartile can be calculated with this data:

135 140 140 143 144 150

And the middle value is:

Q_3 = \frac{140+143}{2}=141.5

The five number summary for this case:

Min. 1st Qu.  Median    Mean 3rd Qu.    Max.  

120.0   130.0   135.0   135.6   141.5   150.0

The boxplot is on the figure attached

8 0
3 years ago
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