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mixer [17]
3 years ago
5

Store Unit Rates Project Which store did you "shop" at? Unit Rate Item Original Rate Example: Eggs (store brand) $1.80 12 30.12

1 $2136 Oreo Sandwich Cookies (price per cookie) Lender's Plain Bagels (price per bagel) Ben and Jerry's Chunky Monkey Ice Cream (price per cup) Kraft Sliced Cheese (price per slice) Sargento Shredded Cheddar Cheese (price per cup) Pop-Tarts (price per pop-tart) Coca-Cola Cans (price per can) Red Delicious Apples 5 lb. Bag (price per pound) Chewy Granola Bar (price per bar) Juicy Juice Juice Boxes (price per juice box) If for some reason you can not find a product, use a similar one as a substitute. Remember that I pint = 2 Cups
PLS help the store I chose was HEB ​
Mathematics
1 answer:
ohaa [14]3 years ago
6 0

Answer:

price per cookie) Lender's Plain Bagels (price per bagel) Ben and Jerry's Chunky Monkey Ice Cream (price per cup) Kraft Sliced Cheese (price per slice) Sargento Shredded Cheddar Cheese (price per cup) Pop-Tarts (price per pop-tart) Coca-Cola Cans (price per can) Red Delicious Apples 5 lb. Bag (price per pound) Chewy Granola Bar (price per bar) Juicy Juice Juice

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Step-by-step explanation:

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3 years ago
Infinite over E n=1 4(0.5)^n-1
yan [13]

Answer:

S = 8

Step-by-step explanation:

An infinite geometric series is defined as limit of partial sum of geometric sequences. Therefore, to find the infinite sum, we have to find the partial sum first then input limit approaches infinity.

However, fortunately, the infinite geometric series has already set up for you. It’s got the formula for itself which is:

\displaystyle \large{\lim_{n\to \infty} S_n = \dfrac{a_1}{1-r}}

We can also write in summation notation rather S-term as:

\displaystyle \large{\sum_{n=1}^\infty a_1r^{n-1} = \dfrac{a_1}{1-r}}

Keep in mind that these only work for when |r| < 1 or else it will diverge.

Also, how fortunately, the given summation fits the formula pattern so we do not have to do anything but simply apply the formula in.

\displaystyle \large{\sum_{n=1}^\infty 4(0.5)^{n-1} = \dfrac{4}{1-0.5}}\\\\\displaystyle \large{\sum_{n=1}^\infty 4(0.5)^{n-1} = \dfrac{4}{0.5}}\\\\\displaystyle \large{\sum_{n=1}^\infty 4(0.5)^{n-1} = 8}

Therefore, the sum will converge to 8.

Please let me know if you have any questions!

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2 years ago
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3 years ago
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Answer:

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Step-by-step explanation:

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