Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
I think Landscape painting
Landscape painting was regarded as the highest form of Chinese painting, and generally still is. The time from the Five Dynasties period to the Northern Song period (907–1127) is known as the "Great age of Chinese landscape".
Answer:
(6, 12)
Step-by-step explanation:
{ 3x - y = 6
{ x - 2y = -18
by using elimination:
6x -2y=12
x - 2y= -18
________-
5x = 30
x = 6
y = 18-6 = 12
the solutions = {(6, 12)}
