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3 years ago

6

Evaluate the expression when a=-7 and c=6. a-6c

1 answer:

beks73 [17]3 years ago

4 0

Answer:

-43

Step-by-step explanation:

(-7) - 6(6)= -43

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IRINA_888 [86]

In the first equation, you can tell that the x's are being multiplied by 3 to get to the y's so the blank will be 9. The second table would not be a function since all the x values are not being multiplied by the same number to get the y value. Hope this helps!

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3 years ago

What is the y-intercept of the line shown below?<br><br>A:3/4<br>B:2<br>C:3<br>D:4

olya-2409 [2.1K]

The y-intercept is the y value where the blue line crosses the Y axis which is the vertical black line.

The line crosses at the number 4, so the y-intercept is 4

Answer: D. 4

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2 years ago

Pls help I need the answer

alexandr402 [8]

Answer:

The first choice.

8 0

2 years ago

Read 2 more answers

Please help homework due

jolli1 [7]

Answer:

X≤3

Step-by-step explanation:

This is because the arrow is moving down the number line

3 0

2 years ago

Point B has coordinates (4,1). The x-coordinate of point A is -4. The distance between point A and point B is 10 units. What a

klasskru [66]

Given:

Point B has coordinates (4,1).

The x-coordinate of point A is -4.

The distance between point A and point B is 10 units.

To find:

The possible coordinates of point A.

Solution:

Let the y-coordinate of point A be y. Then the two points are A(-4,y) and B(4,1).

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The distance between point A and point B is 10 units.

$\sqrt{(4-(-4))^2+(1-y)^2}=10$

Taking square on both sides, we get

$(8)^2+(1-y)^2=100$

$(1-y)^2=100-64$

$(1-y)^2=36$

Taking square root on both sides, we get

$(1-y)=\pm \sqrt{36}$

$-y=\pm 6-1$

$y=1\mp 6$

$y=1-6$ and $y=1+6$

$y=-5$ and $y=7$

Therefore, the possible coordinates of point A are either (-4,-5) or (-4,7).

7 0

2 years ago