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3 years ago

URGENT!!!! PLS HELP MEEE DUE IN 5 MINUTEESS!!

Mathematics

2 answers:

padilas [110]3 years ago

6 0

Answer:

D and C

Step-by-step explanation:

1) The answer is D

g(x) = 2x-8 if we put the corresponding values of x in the table we get the exact same values of y example

$g(x)=2x-8\\g(5)=2(5)-8\\g(5)=2\\g(7)=2(7)=8\\g(7)=6$

so we can see that our values match with the table's values for part D)

2)The answer is C

Range corresponds to the values of y and here the function in the image shows the maximum value of y is 2 and then it decreases to 1 , 0 , -1 and so on so option C is correct y<2

agasfer [191]3 years ago

3 0

Answer:

the answer is c

Step-by-step explanation:

I saw it said it was due in 5 min so i ryed to solve fastt

Hope this helps!

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

(a) Length of AB

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

(b) Are AB and CD congruent

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

(c) AB bisects CD or not?

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

(d) CD bisects AB or not?

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

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3 years ago

Thank yous to whoever solves first. I will mark brainliest

Montano1993 [528]

Answer:

Step-by-step explanation:

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Yuki888 [10]

Answer:

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Step-by-step explanation:

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V=1/3(11.56(15)

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