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3 years ago

ONLY HAVE 5 MINUTES LEFT TO ANSWER NUMBER 4 PLZZZ HELP!

Mathematics

1 answer:

Advocard [28]3 years ago

8 0

Answer:

I dont know if this is right but I think it is 4 3/4 cups

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Convert 0.6 radians to degree measure. Round your answer to the nearest hundredth.

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3 years ago

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What does 11x in the expression represent?

tatiyna

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11x represents the total area of the rectangular playground

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Before a computer is assembled, its motherboard goes through a special inspection. Assume only 85% of motherboards pass this ins

andreyandreev [35.5K]

Answer:

(a) The probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b) On average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

Step-by-step explanation:

Let X = number of motherboards that pass the inspection.

The probability that a motherboards pass the inspection is P (X) = p = 0.85.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is,

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that at least 13 of the next 15 motherboards pass inspection as follows:

P (X ≥ 13) = P (X= 13) + P (X = 14) + P (x = 15)

$={15\choose 13}0.85^{13}(1-0.85)^{15-13}+{15\choose 13}0.85^{14}(1-0.85)^{15-14}\\+{15\choose 13}0.85^{16}(1-0.85)^{15-15}\\=0.2856+0.2312+0.0874\\=0.6042$

Thus, the probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b)

Computed the expected number of motherboards should be inspected until a motherboard that passes inspection is found as follows:

$Expected\ value=\frac{1}{p}=\frac{1}{0.85}= 1.1764\approx1.18$

Thus, on average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

3 0

4 years ago

Please answer ASAP I will give you brainliest

RideAnS [48]

Answer:

a = 11

b = 6

Step-by-step explanation:

$\frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } = a - b \sqrt{3} \\ \\ \frac{(5 + 2 \sqrt{3} )}{(7 + 4 \sqrt{3}) } \times \frac{(7 - 4 \sqrt{3})}{(7 - 4 \sqrt{3})} = a - b \sqrt{3} \\ \\ \frac{(5 + 2 \sqrt{3)} (7 - 4 \sqrt{3} )}{ {(7)}^{2} - {(4 \sqrt{3} )}^{2} } a - b \sqrt{3} \\ \\ \frac{35 - 20 \sqrt{3} + 14 \sqrt{3} - 24 }{49 - 48} = a - b \sqrt{3} \\ \\ \frac{11 - 6 \sqrt{3}}{1} = a - b \sqrt{3} \\ \\ 11 - 6 \sqrt{3} = a - b \sqrt{3} \\ \\ equating \: like \: terms \: on \: both \: \\ sides, \: we \: find : \\ \\ a = 11 \\ \\ b = 6$

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3 years ago

Gary took 7 hours to mow 4 lawns,then at that rate, how many lawns could be mowed in 35 hours? Write a different question plz

Svetach [21]

Answer:

The total amount of lawns to be mowed would be 20 in 35 hours.

Step-by-step explanation:

It takes an hour and 45 minutes to mow one lawn. When you multiply the 7 hours by 5 you get 35 hours. Same thing if you multiply the 4 lawns by 5 you get 20 lawns.

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