The question states that both parts of Noshi's desk were shaped like trapezoids and both had a height of 3.
We know that the formula for area of a trapezoid is (a+b)/2 * h, where a and b are bases of the trapezoid and h is the height. Note: This is like any other form of trying to find the area, because we are doing base times height, however, we need to divide the sum of the bases by 2 to find the average base length.
Let's call the first trapezoid on the left Trapezoid A and the second slanted trapezoid Trapezoid B.
Area of Trapezoid A = (a+b)/2 * h = (5+8)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
Area of Trapezoid B = (a+b)/2 * h = (4+9)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
To find the area of Noshi's total desk, we simply need to add the areas of Trapezoid A and Trapezoid B together.
19.5 feet + 19.5 feet = 39 feet
Therefore, the area of Noshi's desk is 39 feet.
Hope this helps! :)
25/45=(5∗5)/(5∗9)=5/9
5/9 is the answer.
we conclude that the point on this line that is apparent from the given equation is (-6, 6)
<h3>
Which point is on the line, only by looking at the equation?</h3>
Remember that a general linear equation in slope-intercept form is:
y = a*x + b
Where a is the slope.
Here we have the linear equation:
y - 6= (-23)*(x + 6)
Now, for a linear equation with a slope a and a point (h, k), the point slope form of the linear equation is:
(y - k) = a*(x - h)
Now we can compare that general form with our equation, we will get:
(y - k) = a*(x - h)
(y - 6) = (-23)*(x + 6)
Then we have: k = 6 and h = -6.
Thus, we conclude that the point on this line that is apparent from the given equation is (-6, 6).
If you want to learn more about linear equations:
brainly.com/question/1884491
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