Answer:
50, 40, 30, 250, 350
Step-by-step explanation:
1/2 = 0.5, 0.5 x 100 = <u>50</u> (0.5 -> 5 -> 50)
2/5 = 0.4 (10 / 5 [the denominator] = 2, 0.2 x 2 [the numerator] = 0.4), 0.4 x 100 = <u>40</u> (0.4 -> 4 -> 40)
3/10 = (10 / 10 [the denominator] = 1, 0.1 x 3 [the numerator] = 0.3), 0.3 x 100 = <u>30</u> (0.3 -> 3 -> 30)
5/2 = 2.5 (2 1/2), 2.5 x 100 = <u>250</u> (2.5 -> 25 -> 250)
7/2 = 3.5 (3 1/2), 3.5 x 100 = <u>350</u> (3.5 -> 35 -> 350)
Note: I'm not sure if I understand the question completely, but I changed the fraction into a decimal and multiplied it by 100. Not sure what it means by "<u><em>Divide</em></u><em> fraction</em>".
Answer:
The set of solutions is ![\{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number} \}](https://tex.z-dn.net/?f=%5C%7B%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5C%5Cz%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D12%5C%5C-7-r%5C%5Cr%5Cend%7Barray%7D%5Cright%5D%3A%20%5Ctext%7Br%20is%20a%20real%20number%7D%20%20%5C%7D)
Step-by-step explanation:
The augmented matrix of the system is ![\left[\begin{array}{ccccc}3&6&6&-9\\-2&-3&-3&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccc%7D3%266%266%26-9%5C%5C-2%26-3%26-3%263%5Cend%7Barray%7D%5Cright%5D)
.
We will use rows operations for find the echelon form of the matrix.
- In row 2 we subtract
from row 1. (R2- 2/3R1) and we obtain the matrix ![\left[\begin{array}{cccc}3&6&6&-9\\0&1&1&-7\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D3%266%266%26-9%5C%5C0%261%261%26-7%5Cend%7Barray%7D%5Cright%5D)
- We multiply the row 1 by
.
Now we solve for the unknown variables:
The system has a free variable, the the system has infinite solutions and the set of solutions is
Answer:
x = -1
Step-by-step explanation:
Add 4x to each side of the equation
Subtract ⅚ from each side
Divide both sides by -5
Answer:
1.1
Step-by-step explanation:
In this image, we can see that every box, we add 0.2
From 0.1 to 0.3, we add 0.2
We continue with this pattern for the rest of the boxes
When adding decimals, you can imagine it like you are adding normal numbers, and that you are carrying extra (more than 9) to the next column in the same way.
{column/place value}
At first, it might seem like adding 0.2 to 0.9 would result in 0.11, but let's think that through a little bit more. We know that 0.1 is less than 0.2, so, it doesn't make sense for that to be the sum.
Instead, we have to carry the 11 over to the other side of the decimal. (This is because each place value is equal to 10 of the value to the right. If we add digits in the ones place that add up to 10, we carry the "1" over to the right, into the tens place.)
So, we carry the "1" from 11 to the one's place. Now, we are left with
1.1
(hope this helps!! decimals can be tricky at first)
,
,
then