Answer:
<u><em>y' = 1 / sinxcosx</em></u>
Step-by-step explanation:
<u>Given :</u>
y = sinx + cosx / sinx - cosx
<u>Applying quotient rule :</u>
y' = [(sinx - cosx)(cosx - sinx) - (sinx + cosx)(cosx + sinx)] / (sinx -
cosx)²
y' = [sinxcosx - cos²x - sin²x + sinxcosx - (sinxcosx + cos²x + sin²x + sinxcosx)] / (sinx - cosx)²
y' = 2sinxcosx - 2sinxcosx - 2cos²x - 2sin²x / (sinx -cosx)²
y' = -2(sin²x + cos²x) / (sinx - cosx)²
y' = -2 / (sinx - cosx)²
y' = -2 / sin²x - 2sinxcosx + cos²x
y' = -2 / -2sinxcosx
<u><em>y' = 1 / sinxcosx</em></u> [⇒ Final answer]
It would be false to have the same sign.
3a-12b=9 => a = 4b + 3; but, <span>4a-5b=3 => 4(4b + 3) -5b = 3 => 11b = -9 => b = -9/11 => a = -36/11 + 3 = -3/11;</span>
Problem 1
k = Kevin's score
7k = seven times Kevin's score
7k-13 = thirteen fewer than the previous amount = Jason's score of 50
7k-13 = 50
7k = 50+13
7k = 63
k = 63/7
k = 9
<h3>Answer: Kevin scored 9 points</h3>
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Problem 2
p = number of goals Paul scored
6p = six times the previous unknown number
6p-8 = eight fewer than the previous number = Ken's goal count (22)
6p-8 = 22
6p = 22+8
6p = 30
p = 30/6
p = 5
<h3>Answer: Paul scored 5 goals</h3>
Answer:
the answer is b :)
Step-by-step explanation:
