There would be 138 students in 6 classes because first you'd divide 207 from 9 and get 23 then you'd multiply 23 to 6 and get 138.
-4x + 8y = 2
-4x + 4x + 8y = 2 + 4x
8y = 4x + 2
8 8
y = ¹/₂x + ¹/₄
The number of ways for which she could pick four colours if green must be one of them is; 10 ways.
<h3>How many ways can she picks four colours if green must be there?</h3>
It follows from the task that there are 6 colours in total that she could pick from.
Hence, since she needs four colours with green being one of them, it follows that she only has 3 colours to pick from 5.
Hence, the numbers of possible combinations is; 5C3 = 10 ways.
Read more on combinations;
brainly.com/question/2280043
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Answer:
Step-by-step explanation:
Ur answer should be C
