The value of 
.
Solution:
Given equations:
7x + 2y = 57 ---------- (1)
x + 2y = 5 ---------- (2)
Subtract 2y from both sides of the equation (2).
x = 5 – 2y ---------- (3)
Substitute equation (3) in equation (1).
7(5 – 2y) + 2y = 57
35 – 14y + 2y = 57
35 – 12y = 57
Subtract 35 from both sides of the equation.
–12y = 22
Divide by 12 on both sides.
Substitute y value in equation (3).
Hence the value of .
Answer:
5
Step-by-step explanation:
This is how far the number is from 0
Answer:
x(t) = -1 + 4t
y (t) = 3 - 5t
Step-by-step explanation:
The end points of the line segment are (-1, 3) and (3, -2).
Let a = (-1,3) and b = (3,-2)
Now, find the value of (b-a)
(b-a) = ((3+1), (-2-3))
b-a = (4, -5)
Therefore, the parametrization of the given line segment is
r(t) = a + (b-a)t
r(t) = (-1,3) +(4,-5)t
r(t) = (-1+4t, 3-5t)
We can rewrite this as
x(t) = -1 + 4t
y (t) = 3 - 5t
Xy (less than or equal to sign) 4
W = width
<span>w + 6 = length </span>
<span>2w + 2(w + 6) = 64 </span>
<span>2w + 2w + 12 = 64 </span>
<span>4w = 64 - 12 = 52 </span>
<span>w = 52 ÷ 4 so see what that is and plug it in to answer the question.</span>
