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Allisa [31]
3 years ago
14

3100 times 43 how much is this

Mathematics
2 answers:
Soloha48 [4]3 years ago
7 0

Answer:

133,300

Step-by-step explanation:

3100 x 43 = 133,300

const2013 [10]3 years ago
3 0

Answer: 133,300

Step-by-step explanation: 3100 x 43= 133300

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George was writing a paper for English class. He has already written 1 complete page. He plans on writing his paper at a rate of
ira [324]

Answer:

y=2x+1

put a point at +1 on the graph. go up two and right one from there and draw a line from those points

Step-by-step explanation:

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3 years ago
Write the linear equation in slope-intercept form 2x - 3y = 6
noname [10]
2x - 3y = 6
3y = -2x + 6

y = -\frac{2}{3}x + 2

m = -\frac{2}{3}
c  = 2

Linear Equation: 
y = -\frac{2}{3}x + 2
7 0
3 years ago
Paul deposited $95,000 in a savings account that pays 4% interest compounded daily. What is his balance at the end of six months
Arada [10]

Answer:

\$96,919.02  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=6/12=0.5\ years\\ P=\$95,000\\ r=4\%=4/100=0.04\\n=365  

substitute in the formula above  

A=95,000(1+\frac{0.04}{365})^{365*0.5}  

A=95,000(1+\frac{0.04}{365})^{182.5}=\$96,919.02  

5 0
3 years ago
Kay is using cone-shaped party hats as popcorn holders. The party hats have a diameter of 10 inches and a height of 9 inches. Ho
vampirchik [111]
I think that the answer is B.
6 0
3 years ago
Read 2 more answers
Problem PageQuestion The mass of a radioactive substance follows a continuous exponential decay model, with a decay rate paramet
asambeis [7]

Answer:

<em>t = 1.51</em>

Step-by-step explanation:

<u>Exponential Model</u>

The exponential model is often used to simulate the behavior of a magnitude that either grow or decay in proportion to the existing amount of that magnitude.

The model can be expressed as

M=M_oe^{kt}

In this case, Mo is the initial mass of the radioactive substance and k is a constant which value is positive if the mass is growing or negative if the mass is decaying.

The value of k is not precisely given in the question, we are assuming k=-0.2

The model is now

M=M_oe^{-0.2t}

We are required to compute the time it takes the mass to reach one-half of its initial value:

\displaystyle \frac{M_o}{2}=M_oe^{-0.2t}

Simplifying

\displaystyle \frac{1}{2}=e^{-0.2t}

Taking logarithms

\displaystyle ln\frac{1}{2}=ln(e^{-0.2t})=-0.2t

Solving for t

\displaystyle t=-\frac{ln\frac{1}{2}}{0.2}=1.51

6 0
3 years ago
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