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3 years ago

Can help me howMacam mana...

Mathematics

2 answers:

Alborosie3 years ago

8 0

Step-by-step explanation:

2(x+2)=7

2x+4=7

2x=7-4

2x=3

x=3/2

ii)3x + y =8 , y=x

3x + x = 8

4x = 8

x = 2

Tresset [83]3 years ago

4 0

Answer:

x = 2

Step-by-step explanation:

2(x+2)=7

2x+4=7

2x=7-4

2x=3

x=3/2

3x + y =8 , y=x

3x + x = 8

4x = 8

x = 2

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Use the properties of logarithms to prove log, 1000 = log2 10.

Leto [7]

Given:

Consider the equation is:

$\log_81000=\log_210$

To prove:

$\log_81000=\log_210$ by using the properties of logarithms.

Solution:

We have,

$\log_81000=\log_210$

Taking left hand side (LHS), we get

$LHS=\log_81000$

$LHS=\dfrac{\log 1000}{\log 8}$ $\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]$

$LHS=\dfrac{\log (10)^3}{\log 2^3}$

$LHS=\dfrac{3\log 10}{3\log 2}$ $[\because \log x^n=n\log x]$

$LHS=\dfrac{\log 10}{\log 2}$

$LHS=\log_210$ $\left[\because \log_ab=\dfrac{\log_x a}{\log_x b}\right]$

$LHS=RHS$

Hence proved.

6 0

3 years ago

Hiii!!!!!!!!!!!!!!!!!!

sergeinik [125]

Answer:

Hi!

Step-by-step explanation:

How are you?

8 0

3 years ago

Read 2 more answers

Use a single digit times a power of 10 to express the number 866,214,000,000

BartSMP [9]

Answer:

8.66214 x 10^11

Step-by-step explanation:

question may ask to round, so the answer may be simplified to 9 x 10^11

3 0

3 years ago

What is the slope of a line parallel to the line whose equation is3x−4y=8?

xxTIMURxx [149]

The slope of the parallel line is 3/4

<h3>How to determine the slope?</h3>

The equation is given as:

3x - 4y = 8

Rewrite as:

4y = 3x - 8

Divide through by 4

y = 3x/4 - 2

A linear equation is represented as:

y = mx + b

Where m represents the slope

By comparison:

m = 3/4

Parallel lines have equal slope

Hence, the slope of the parallel line is 3/4

Read more about slope at:

brainly.com/question/3493733

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7 0

2 years ago

X2 - 6x + 12 and y = 2x - 4, algebraically are

olga_2 [115]

The solution is (4, 4)

Solution:

Given system of equations are:

$y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2$

Substitute eqn 2 in eqn 1

$x^2 - 6x + 12 = 2x - 4$

Make the right side of equation 0

$x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0$

Solve by quadratic equation

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4$

Substitute x = 4 in eqn 2

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0

3 years ago

Can help me howMacam mana... ​

Can help me howMacam mana...