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mezya [45]
3 years ago
14

Find the missing value. Hint: Use the number line to find the missing value. -5=_+6

Mathematics
2 answers:
Mumz [18]3 years ago
4 0
I think it’s is -12 but I am not to sure
alex41 [277]3 years ago
3 0

Answer:

-11 isay

Step-by-step explanation:

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△FOD~△HOG. Identify the coordinates of D and the scale factor. HELP PLEASE!!
cupoosta [38]

Answer:

Option D. (0,-20/3), \frac{2}{3}

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is equal

so

\frac{OH}{OF}=\frac{OG}{OD}

substitute values and solve for OD

\frac{6}{4}=\frac{10}{OD}

OD=10*4/6=20/3

therefore

the coordinate of point D is (0,-20/3)

the scale factor is equal to \frac{OF}{OH}=\frac{4}{6}=\frac{2}{3}

8 0
3 years ago
SOLVE CORRECTLY FOR BRAINLIEST! QUESTION DISPLAYED BELOW:
Dmitry_Shevchenko [17]

Answer:

2

Step-by-step explanation:

We are given:

t = -11
u = 11
v = 1

Plug in the values to (tv-u) / tv:

((-11)(1) - 11) / (-11)1
(-11-11) / -11
-22 / -11
= 2

4 0
3 years ago
Find AA and BB that make the equation true. Verify your results.
CaHeK987 [17]

Answer:

a. A = -1 and B = 1

b. A = 7 and B = -5

Step-by-step explanation:

a.

\frac{A}{x+1} +\frac{B}{x-1}  = \frac{2}{x^2-1}

\frac{A*(x-1)+B*(x+1)}{(x+1)*(x-1)} = \frac{2}{x^2-1}

\frac{Ax - A + Bx + B}{x^2 -1} = \frac{2}{x^2-1}

To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:

Ax + Bx = 0

(A + B)x = 0

A + B = 0

A = -B

B - A = 2

B - (-B) = 2

2B = 2

B = 1  and A = -1

b.

\frac{A}{x+3} + \frac{B}{x +2} = \frac{2x -1}{x^2+5x+6}

\frac{A*(x+2) + B*(x+3)}{(x+3)*(x+2)} = \frac{2x-1}{x^2+5x+6}

\frac{Ax + 2A + Bx + 3B}{x^2 + 5x + 6} = \frac{2x-1}{x^2+5x+6}

To the equation be true, the "x-parts" and "nonx-parts" mist be the same, so:

Ax + Bx = 2x

(A + B)x = 2x

A + B = 2

A = 2 - B

2A + 3B = -1

2*(2-B) + 3B = -1

4 - 2B + 3B = -1

B = -5  and A = 2 - (-5) = 7

5 0
4 years ago
Ahhhhhhhhhhhhhhhhhhhhhhhhhhh​
Ber [7]

Answer:

5+b=11

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
4.) Complete the equations of the system in slope-intercept form. Use a decimal for the slope if necessary.
marissa [1.9K]
The slope is found by y_{2} -y_{1} / x_{2}  - x_{1}
Line 1: y2 is 6, y1 is 4, x2 is 2, x1 is -2
6-4/2- -2= 2/4=1/2

Slope intercept is written as y= mx+b. m is the slope, and b is the intercept (the intercept is the value of y when x is 0). To find out the intercept, we plug in values of y, m and x
4= 1/2(-2) +b
4=-1+b
5=b
The equation for line 1 is y= 1/2x +5
Using the same formulas as above, the equation for line 2 is y= 3x+4
The solution to the system is a point where both lines would meet in the graph, or a set of x and y values that satisfies both equations. 
y= 3x+4
y= 1/2x+5
3x+4 = 1/2x+5
3x= 1/2x +5 -4
3x= 1/2x +1
3x-1/2x= 1
2.5x=1
2.5x/2.5=1/2.5
x=0.4
Plug 0.4 into the slope intercept equation
y= 3(0.4) +4
y= 1.2 +4
y=5.2

y= 1/2(0.4) +5
y= 0.2 +5
y= 5.2
The solution is 0.4, 5.2

The other set of lines
Line 1: y= 3x+2
Line 2: y= -2x +7
Solution: 1,5
4 0
4 years ago
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