A rocket gets launched straight up into space. What is a possible description
1 answer:
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Answer:
y = x + 5
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
f(x) = - 2x + 1 ← is in slope- intercept form
with slope m = - 2
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
=
, then
y = x + c
the line crosses the y- axis at (0, 5 ) ⇒ c = 5
y = x + 5 ← equation of perpendicular line