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kipiarov [429]
3 years ago
8

It is 170 miles from Bruce's house to the city where his brother lives. On his last trip to visit his brother, he drove for 2 ho

urs at 55 miles per hour. Then he came to some very bad road construction. The rest of the trip took 2 hours. How many miles per hour did Bruce drive for the rest of the trip?
Mathematics
1 answer:
Rom4ik [11]3 years ago
5 0

Speed of Bruce for the rest of the trip is 30 miles/hour.

Step-by-step explanation:

  • Step 1: Total distance = 170 miles. In the trip Bruce's speed = 55 miles/hour. So, in 1 hour, distance covered = 55 miles. Find distance covered in 2 hours and the distance of the last part.

Distance covered in 2 hours = 2 × 55 = 110 miles

Remaining part of the trip = 170 - 110 = 60 miles

  • Step 2: Find the speed of Bruce in the remaining part of the trip when time = 2 hours and distance = 60 miles.

Speed = Distance/Time = 60/2 = 30 miles/hour

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What is the answer to this??
Helga [31]

Since the triangle is equilateral, all its angles are equal to 60°

AO is the bisector⇒∠OAD = 30°

AO AO is the hypotenuse, ∠OAD = 30°⇒

OD=10:2=5ft

By the Pythagorean theorem

10^2=AD^2+5^2\\AD=\sqrt{100-25} \\AD=\sqrt{75}

AC=AD+DC=2\sqrt{75}=10\sqrt{3}

S=\frac{a^2\sqrt{3} }{4}

S=\frac{(10\sqrt{3})^2\sqrt{3}  }{4} =\frac{300\sqrt{3} }{4} =75\sqrt{3} ft^2

Answer: A) S=75\sqrt{3}ft²

P.S. Hello from Russia and sorry for my bad english :^)

5 0
4 years ago
The tax on a property with an assessed value of $90,000 is $1,200. What is the assessed value of a property if the tax is $2,200
Ivanshal [37]
I'm not 100% sure but this is how I would try.
If you don't get a better answer, check this w/your teacher.

x/100 *90,000 = 1200

90,000x = 120,000

x = 1.3% tax percentage

1.3/100x = 2200

1.3x = 220,000

x = $169,230.77 assessed value

5 0
3 years ago
The price of an item yesterday was $120 . Today, the price fell to $54 . Find the percentage decrease.
Nesterboy [21]

Answer:

magnitude of decrease = 120 - 54 = 66$

the percentage = (66/100)×100 = 66%

8 0
3 years ago
"The counting rule that is used for counting the number of experimental outcomes when n objects are selected from a set of N obj
Liula [17]

<u>Options</u>

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Answer:

(C)Counting rule for combinations

Step-by-step explanation:

When selecting n objects from a set of N objects, we can determine the number of experimental outcomes using permutation or combination.

  • When the order of selection is important, we use permutation.
  • However, whenever the order of selection is not important, we use combination.

Therefore, The counting rule that is used for counting the number of experimental outcomes when n objects are selected from a set of N objects where order of selection is not important is called the counting rule for combinations.

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What multiplication problem matches this addition problem?
tiny-mole [99]
6*7=42
It’s the answer I guess.
8 0
3 years ago
Read 2 more answers
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