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3 years ago

Which pair of equations can be used to solve for x in PQR?

Mathematics

1 answer:

almond37 [142]3 years ago

7 0

Answer:

Step-by-step explanation:

sin57° = $\frac{opposite}{hypotenuse}$ = $\frac{PQ}{PR}$ = $\frac{x}{18}$

∠ P = 180° - (90 + 57)° ← sum of angles in triangle

∠ P = 180° - 147° = 33° , then

cos33° = $\frac{adjacent}{hypotenuse}$ = $\frac{PQ}{PR}$ = $\frac{x}{18}$

Thus the 2 ratios used to solve for x are A

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Which statement holds true for a skewed histogram showing a distribution of the weights of students in a class?

Vanyuwa [196]

Among the choices, the statement which describes a skewed histogram showing a distribution of the weights of students in a class is:

<span>"The nature of the skew can be verified by the position of the mean with respect to the mode."

The histogram is skewed to the right if the mean is less than the mode and the histogram is skewed to the left if the mean is more than the mode. </span><span />

8 0

3 years ago

Simplify two to the fifth power over three to the second power

Savatey [412]

[/tex] $\frac{32}{9}$
This changes to a mix fraction
3 [tex] \frac{5}{9}

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4 years ago

For A I somehow got 41.05 but its 2.95cm can someone show me the working and what I did wrong?

777dan777 [17]

Answer:

Step-by-step explanation:

a). tan(75°) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

= $\frac{11}{k}$

k = $\frac{11}{\text{tan}(75)}$

k = 2.947

k = 2.95 cm

b). cos(52°) = $\frac{16}{s}$

s = $\frac{16}{\text{cos}(52)}$

s = 25.988

s ≈ 25.99 cm

c). sin(5°) = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

= $\frac{16.1}{q}$

q = $\frac{16.1}{\text{sin}(5)}$

q = 184.727

q ≈ 184.73 cm

4 0

3 years ago

Which graph corresponds with the equation <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B1%7D%7B2%20%7D%20%28x%2B1%29%5E

JulijaS [17]

$\qquad\qquad\huge\underline{{\sf Answer}}$

The given equation is a Quadratic equation, so it's graph must be a parabola, and the Coefficient of x² is positive that means the parabola must have an opening upward.

And 2 is added to the ideal equation, so the parabola must have shift 2 units up from x - axis.

From the above information, we can easily conclude that the Correct representation is done in graph 4

5 0

2 years ago

Which expression is equivalent to:1/m6

Valentin [98]

Answer:

Step-by-step explanation:

6 is a power. So both C and D are wrong because 6 is being treated as an ordinary integer.

So the answer must be either A or B.

B is not correct because to move an expression from the denominator to the numerator changes the sign in the base (which is m in this question).

A is correct. the power is changed from 6 in the denominator to -6 in the numerator. m is shifted to the numerator as well.

8 0

3 years ago