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Makovka662 [10]
3 years ago
6

Which pair of equations can be used to solve for x in PQR?

Mathematics
1 answer:
almond37 [142]3 years ago
7 0

Answer:

A

Step-by-step explanation:

sin57° = \frac{opposite}{hypotenuse} = \frac{PQ}{PR} = \frac{x}{18}

∠ P = 180° - (90 + 57)° ← sum of angles in triangle

∠ P = 180° - 147° = 33° , then

cos33° = \frac{adjacent}{hypotenuse} = \frac{PQ}{PR} = \frac{x}{18}

Thus the 2 ratios used to solve for x are A

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Since Perimeter = 58 m
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3 years ago
If costheta=4/5 then what is sec^2theta
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Answer:

\sec^2(\theta)=\frac{25}{16}

Step-by-step explanation:

Recall what the relationship between cosine and secant:

\sec(\theta)=\frac{1}{\cos(\theta)}

In other words, secant is the reciprocal of cosine.

So, if we know cosine, we only need to find its reciprocal to find secant.

We are given that cosine is:

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Then secant must be:

\sec(\theta)=\frac{5}{4}

So:

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Square:

\sec^2(\theta)=\frac{25}{16}

And we're done!

5 0
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How can I explain with mental math
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Answer:

Step-by-step explanation:

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