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Makovka662 [10]
3 years ago
6

Which pair of equations can be used to solve for x in PQR?

Mathematics
1 answer:
almond37 [142]3 years ago
7 0

Answer:

A

Step-by-step explanation:

sin57° = \frac{opposite}{hypotenuse} = \frac{PQ}{PR} = \frac{x}{18}

∠ P = 180° - (90 + 57)° ← sum of angles in triangle

∠ P = 180° - 147° = 33° , then

cos33° = \frac{adjacent}{hypotenuse} = \frac{PQ}{PR} = \frac{x}{18}

Thus the 2 ratios used to solve for x are A

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