2 years ago

Which pair of equations can be used to solve for x in PQR?

Mathematics

1 answer:

almond37 [142]2 years ago

7 0

Answer:

Step-by-step explanation:

sin57° = $\frac{opposite}{hypotenuse}$ = $\frac{PQ}{PR}$ = $\frac{x}{18}$

∠ P = 180° - (90 + 57)° ← sum of angles in triangle

∠ P = 180° - 147° = 33° , then

cos33° = $\frac{adjacent}{hypotenuse}$ = $\frac{PQ}{PR}$ = $\frac{x}{18}$

Thus the 2 ratios used to solve for x are A

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