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nexus9112 [7]
3 years ago
7

The average of their maximum speeds was 260 km/h. If doubled Malcolm’s maximum speed would be 80 km/h more than Ravi’s maximum s

peed. What were Malcolm’s and Ravi’s maximum speeds?
Mathematics
1 answer:
san4es73 [151]3 years ago
7 0

Answer:

Malcolm’s maximum speed is 200 km/h and and Ravi’s maximum speeds is 320 km/h.

Step-by-step explanation:

Let x and y are the maximum speeds ( in  km / h ) of Malcolm and Ravi respectively,

Then according to the question,

\frac{x+y}{2}=260

\implies x + y = 520-----(1)

Again according to the question,

2x = y + 80

\implies 2x - y = 80----(2)

Equation (1) + equation (2),

3x = 600

⇒ x = \frac{600}{3} = 200,

From equation (1),

200 + y = 520

⇒ y = 520 - 200 = 320

Hence,  Malcolm’s and Ravi’s maximum speeds are 200 km/h and 320 km/h respectively.

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7.1 points

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100/14=7.1 points

3 0
2 years ago
What is the area of the poster board that she has left
steposvetlana [31]
Find the area of the parallelogram, find the area of the triangle, then subtract the triangle's area from the area of the parallelogram.

Area of Parallelogram:
A= base * height
A= 20 in * 10 in
A= 200 in^2

Area of Triangle:
A= 1/2 base * height
A= 1/2 (10 in)(9 in)
A= 1/2 (90)
A= 45 in ^2

Area of Poster Left:
subtract the difference
A= Parallelogram Area - Triangle Area
A= 200 in^2 - 45 in^2
A= 155 in^2

ANSWER: 155 in^2 is the area of the poster board she has left.

Hope this helps! :)
5 0
3 years ago
Find the value of the variables​
Ierofanga [76]

Answer:

Your answer is.....

x= 10.58

y= 21.66

Mark it as brainlist answer . follow me for more answer.

Step-by-step explanation:

4 0
3 years ago
Megan makes $480 a week and her boss wanted to give her
wel

Answer:

$537.60

Step-by-step explanation:

12% increase is the same as multiplying by 1.12, 480*1.12=537.60

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Consider an experiment with sample space S 5 50, 1, 2, 3, 4, 5, 6, 7, 8, 96 and the events A 5 {0, 2, 4, 6, 8} B 5 {1, 3, 5, 7,
Brut [27]

Answer with Step-by-step explanation:

S={0,1,2,3,4,5,6,7,8,9}

A={0,2,4,6,8}

B={1,3,5,7,9}

C={0,1,2,3,4}

D={5,6,7,8,9}

a.A'=S-A

A'={0,1,2,3,4,5,6,7,8,9}-{0,2,4,6,8}

A'={1,3,5,7,9}

b.C'=S-C

C'={0,1,2,3,4,5,6,7,8,9}-{0,1,2,3,4}

C'={5,6,7,8,9}

c.D'=S-D

D'={0,1,2,3,4,5,6,7,8,9}-{5,6,7,8,9}

D'={0,1,2,3,4}

d.A\cup B={0,2,4,6,8}\cup{1,3,5,7,9}

A\cup B={0,1,2,3,4,5,6,7,8,9}=S

e.A\cup C={0,2,4,6,8}\cup{0,1,2,3,4}

A\cup C={0,1,2,3,4,6,8}

f.A\cup D={0,2,4,6,8}\cup{5,6,7,8,9}

A\cup D={0,2,4,5,6,7,8,9}

8 0
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