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Harrizon [31]
3 years ago
9

Find 4 solutions (in radians) of sine = 0.18.

Mathematics
1 answer:
mezya [45]3 years ago
4 0

9514 1404 393

Answer:

  0.180986, 2.96061, 6.46417, 9.24379

Step-by-step explanation:

The first solution to ...

  sin(x) = 0.18

is found by using the arcsine function:

  x = arcsin(0.18) ≈ 0.180986

Additional positive values can be found by subtracting this angle from π, and by adding multiples of 2π to either of the values obtained so far.

  π - 0.180986 ≈ 2.96061

Adding 2π to these gives two more values:

  0.180986 +2π ≈ 6.46417

  2.96061 +2π ≈ 9.24379

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3 years ago
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A number, added to its three quarters, is equal to its double decreased by 6. What is the number
faust18 [17]

Answer:

9

Step-by-step explanation:

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7 0
2 years ago
2. Change the following statements into coordinate points and then plot them!
GREYUIT [131]

Answer:

The points are (-1, 1), (2, 7), (1, -1), (3, 0)

Step-by-step explanation:

Let us solve the question

∵ f(x) = y

∴ The coordinates of the point are (x, y)

→ Let us use this fact to find the coordinates of each point

∵ f(-1) = 1

∴ x = -1 and y = 1

∴ The coordinates of the point are (-1, 1)

∵ f(2) = 7

∴ x = 2 and y = 7

∴ The coordinates of the point are (2, 7)

∵ f(1) = -1

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∴ The coordinates of the point are (1, -1)

∵ f(3) = 0

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The graph is attached down

8 0
2 years ago
In the figure below, AB=AE, AC=AD and AP is perpendicular to BE. Prove that BC=DE.
NISA [10]

Step-by-step explanation:

1) In the figure, as AB is equal to AE, ABE is an equilateral triangle.

As AP is perpendicular to BE

=> AP is the height of the triangle ABE.

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle.

=> P is the midpoint of BE

=> PE = PB

2) In the figure, as AC = AD, so that ACD is an equilateral triangle.

As AP is perpendicular to BE,  so that it is perpendicular to CD as well

=> AP is the height of the triangle ACD

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle ACD.

=> P is the midpoint of CD

=> PC = PD

We have:

+) PB = PE

+) PC = PD

=> PB - PC = PE - PD => BC = DE

5 0
3 years ago
Please Help!
Lisa [10]
We know that

in the right triangle
sin x=opposite side angle x/hypotenuse
opposite side angle x=66 mm
hypotenuse=79 mm
so
sin x=66/79
x=arc sin (66/79)-------> x=56.66°-------> x=56.7°

the answer is
x=56.7°
7 0
3 years ago
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