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gladu [14]
3 years ago
11

What's the answer to this problem.

Mathematics
2 answers:
frutty [35]3 years ago
8 0
The answer is B. by SAS
sweet-ann [11.9K]3 years ago
6 0
The answer is B because SAS stands for side-angle-side

So, the side JK is marked congruent to side PQ
Then angle K is marked congruent to Q
Finally, side KL is marked congruent to QR


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Write a decimal expression that has the same value as 2.5 divided .5-1.4
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Find the product. (-3ab 2)3 27ab -23a2b2 -9a3b5 -27a3b6
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Answer:

Step-by-step explanation:

(-3 ab²)³=(-3)³(a)³(b²)³=-27 a³b^(2×3)=-27 a³b^6

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2 years ago
The 2nd, 6th, 8th terms of an A.P. form a G.P. , find the common ratio and the general term of the G.P.​
melisa1 [442]

The terms of an arithmetic progression, can form consecutive terms of a geometric progression.

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  • The general term of the GP is: \mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

The nth term of an AP is:

\mathbf{T_n = a + (n - 1)d}

So, the <em>2nd, 6th and 8th terms </em>of the AP are:

\mathbf{T_2 = a + d}

\mathbf{T_6 = a + 5d}

\mathbf{T_8 = a + 7d}

The <em>first, second and third terms </em>of the GP would be:

\mathbf{a_1 = a + d}

\mathbf{a_2 = a + 5d}

\mathbf{a_3 = a + 7d}

The common ratio (r) is calculated as:

\mathbf{r = \frac{a_2}{a_1}}

This gives

\mathbf{r = \frac{a + 5d}{a + d}}

The nth term of a GP is calculated using:

\mathbf{a_n = a_1r^{n-1}}

So, we have:

\mathbf{a_n = (a + d) \times (\frac{a + 5d}{a + d})^{n-1}}

Read more about arithmetic and geometric progressions at:

brainly.com/question/3927222

6 0
2 years ago
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