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liubo4ka [24]
3 years ago
10

Which nuclear equation represents a natural transmutation?

Chemistry
1 answer:
pashok25 [27]3 years ago
3 0
I can tell you about:


- What natura transmutation is

- Which elements suffer natural transmutation

- Some examples of nuclear equation representing natural transmutation



1) Natural transmutation is the transmutation that occurs in nature without intervention of human beings. So, the natural transmutation is the natural decay of elements into other (smaller) elements. The transmutation of the elements consists in the emission of particles (alpha emission, beta emission, positron emission or electron emission) and the obtention of a smaller element.



2) Which elements undergo natural transmutation.


The heavier elements, after lead, are radioactive and so they decay into lighter (smaller) elements. Those elements are unstable due to the relation proton / neutron.   


3) Transmutation equation examples


I131 ----> Xe131 + Beta particle


Ra222 ---> Rn218 + 2He4 (same alpha particle)


90Th234 ----> 89Pa234 + beta particle
 

92U238 ----> 90Th 234 + 2He4   (same alpha particle)



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4 years ago
The pH of a solution is measured to be pH=10. What is true of this solution?
Marta_Voda [28]

Answer:

a. the solution is a base

Explanation:

The pH range is between 0 to 14.

A solution with a pH value between 0 and 6 is said to be acidic.

A solution with pH value at 7, is said to be neutral, e.g., distilled water.

A solution with pH value between 8 and 14 is a base.

Given pH = 10, a pH value of 10 falls between the base or alkali range of the indicator

8 0
4 years ago
Is PCl3 ionic or covalent?
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Answer:

covalent

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8 0
4 years ago
The vapor pressure of a system at equilibrium
Marizza181 [45]

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Explanation:

3 0
3 years ago
The element boron exists in nature as two isotopes: 10B has a mass of 10.0129 u, and 11B has a mass of 11.0093 u. The average at
Shalnov [3]

Answer:

Percentage abundance of B 10 is = 20 %

Percentage abundance of B 11 is = 80 %

Explanation:

The formula for the calculation of the average atomic mass is:

Average\ atomic\ mass=(\frac {\%\ of\ the\ first\ isotope}{100}\times {Mass\ of\ the\ first\ isotope})+(\frac {\%\ of\ the\ second\ isotope}{100}\times {Mass\ of\ the\ second\ isotope})

Given that:

Since the element has only 2 isotopes, so the let the percentage of first be x and the second is 100 -x.

For first isotope, B 10:

% = x %

Mass = 10.0129 u

For second isotope, B 11:

% = 100  - x  

Mass = 11.0093 u

Given, Average Mass = 10.81 u

Thus,  

10.81=\frac{x}{100}\times {10.0129}+\frac{100-x}{100}\times {11.0093}

10.0129x+11.0093\left(100-x\right)=1081

Solving for x, we get that:

x = 20 %

Thus percentage abundance of B 10 is = 20 %

Percentage abundance of B 11 is = 100 - 20 %  = 80 %

8 0
3 years ago
Read 2 more answers
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