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Oduvanchick [21]
3 years ago
12

Refer to the activity series chart and determine which of the following displacement reactions can occur.

Chemistry
1 answer:
Citrus2011 [14]3 years ago
4 0
<span>Among the choices provided, the answer is letter C, CuSO4(aq) + Fe(s) → FeSO4(aq) + Cu(s) since Iron(Fe) is higher up on the action graph and is, along these lines, more responsive than Copper(Cu). Because of this, Iron can supplant Copper in that substance equation. </span>
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phosphorus trifluoride is formed from its elements P4 (s) F2 (g) ---&gt; PF3 (g) how many grams of fluorine are needed to react
Oksi-84 [34.3K]

This is an incomplete question, here is a complete question.

Phosphorus trifluoride is formed from its elements.

P_4(s)+6F_2(g)\rightarrow 4PF_3(g)

How many grams of fluorine are needed to react with 6.20 g of phosphorus?

Answer : The mass of F_2 needed are, 11.4 grams.

Explanation : Given,

Mass of P_4 = 6.20 g

Molar mass of P_4 = 124 g/mol

Molar mass of F_2 = 38 g/mol

First we have to calculate the moles of P_4

\text{Moles of }P_4=\frac{\text{Given mass }P_4}{\text{Molar mass }P_4}

\text{Moles of }P_4=\frac{6.20g}{124g/mol}=0.05mol

Now we have to calculate the moles of F_2

The balanced chemical equation is:

P_4(s)+6F_2(g)\rightarrow 4PF_3(g)

From the balanced reaction we conclude that

As, 1 mole of P_4 react with 6 moles of F_2

So, 0.05 moles of P_4 react with 0.05\times 6=0.30 moles of F_2

Now we have to calculate the mass of F_2

\text{ Mass of }F_2=\text{ Moles of }F_2\times \text{ Molar mass of }F_2

\text{ Mass of }F_2=(0.30moles)\times (38g/mole)=11.4g

Therefore, the mass of F_2 needed are, 11.4 grams.

4 0
3 years ago
I need help please i need it today
creativ13 [48]

Answer:

what help.....

i don't understand your question what help....

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