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2 years ago

Refer to the activity series chart and determine which of the following displacement reactions can occur.

Chemistry

1 answer:

Citrus2011 [14]2 years ago

4 0

<span>Among the choices provided, the answer is letter C, CuSO4(aq) + Fe(s) → FeSO4(aq) + Cu(s) since Iron(Fe) is higher up on the action graph and is, along these lines, more responsive than Copper(Cu). Because of this, Iron can supplant Copper in that substance equation. </span>

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Which material has carbon atoms interspersed with iron atoms in its molecular structure?

gogolik [260]

Answer:

steel should be correct

4 0

2 years ago

A student sees an absorbance a=1.140 for his solution that has a concentration of c=1.50*10-4 m using 0.50 cm cuvette. what is t

777dan777 [17]

The molar extinction coefficient is 15,200 $M^{-1} cm^{-1}$ .

The formula to be used to calculate molar extinction coefficient is -

A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.

The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.

Rewriting the formula as per molar extinction coefficient -

ξ = $\frac{A}{cl}$

ξ = $\frac{1.140}{1.5*10^{-4}*0.5 }$

Performing multiplication in denominator to find the value of molar extinction coefficient

ξ = $\frac{1.140}{0.000075}$

Performing division to find the value of molar extinction coefficient

ξ = 15,200 $M^{-1} cm^{-1}$

Hence, the molar extinction coefficient is 15,200 $M^{-1} cm^{-1}$ .

Learn more about molar extinction coefficient -

brainly.com/question/14744039

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6 0

1 year ago

If a compound has a log kow value of 6.5, what would be its predicted concentration (in ppm) in the fat of fish that swim in wat

blsea [12.9K]

Easy ans I don't know .......

5 0

3 years ago

How many atoms of gold are in gold nugget with a mass of 4.25 g

Feliz [49]

Number of Atoms in Gold for given mass can be calculated using following formula,

# of Moles = Number of Atoms / 6.022 × 10²³
Or,
Number of Atoms = Moles × 6.022 × 10²³ ------- (1)

Calculating Moles,
As,
Moles = Mass / M.mass
So,
Moles = 4.25 g / 196.96 g/mol

Moles = 0.0215

Putting value of mole in eq.1,

Number of Atoms = 0.0215 × 6.022 × 10²³

Number of Atoms = 1.299 × 10²²

Result:
4.25 g of Gold Nugget contains 1.299 × 10²² Atoms.

3 0

3 years ago

Read 2 more answers

"What volume of" a 0.300 M BaF2 "solution is needed to prepare" 240.0 mL of a 0.100 M F- solution

zhannawk [14.2K]

Use M x V = M' x V'

0.300 x V = 0.100 x 250

V = .......... ml

6 0

3 years ago