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3 years ago

The vapor pressure of a system at equilibrium

1 answer:

3 0

Answer: The vapor pressure or equilibrium vapor pressure is defined as the pressure exerted by a vapor that is in thermodynamic equilibrium with the condensed phase (solid or liquid) at a given temperature in a closed system. The equilibrium vapor pressure is an indication of the evaporation rate of a liquid.

Explanation:

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What is the mass of carbon in 500. g of octane?

denis23 [38]

The answer is: the mass of carbon is 420.6 grams.

m(C₈H₁₈) = 500 g; mass of octane.

M(C₈H₁₈) = 114.22 g/mol; molar mass of octane.

n(C₈H₁₈) = m(C₈H₁₈) ÷ M(C₈H₁₈).

n(C₈H₁₈) = 500 g ÷ 114.22 g/mol.

n(C₈H₁₈) = 4.38 mol; amount of octane.

In one molecule of octane, there are eight carbon atoms:

n(C) = 8 · n(C₈H₁₈).

n(C) = 8 · 4.38 mol.

n(C) = 35.02 mol; amount of carbon.

m(C) = 35.02 mol · 12.01 g/mol.

m(C) = 420.6 g; mass of carbone.

5 0

3 years ago

What process in the carbon cycle takes carbon out of air?

Veronika [31]

It is photosynthesis
<span>
photosynthesis is the process by which green plants and some other organisms use sunlight to synthesize foods from carbon dioxide and water. photosynthesis in plants generally involves the green pigment chlorophyll and generates oxygen as a byproduct, hope it helps</span>

7 0

3 years ago

Select each process that shows a physical change. Select all that apply.

erica [24]

Answer:

Chopping wood logs

A pot of water o a grate over a burning fire

Explanation:

Physical change is easily reversible. Burning/combustion is a chemical process where substances react rapidly with oxygen: this is usually irreversible.

The marshmallow, roasted food and burned wood all undergo combustion and hence are tagged chemical changes.

Explanation:

5 0

3 years ago

Read 2 more answers

In a titration experiment a student uses 1.4 m hbr solution and the indicator phenolphthalein to determine the concentration of

Likurg_2 [28]

The question is incomplete. Complete question is attached below:
...........................................................................................................................

Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL

We know that, M1V1 = M2V2
(HBr) (KOH)

Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M

Concentration of KOH is 0.9756 M.

3 0

3 years ago

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According to the law of conservation of mass, the total mass of the reactants is

yarga [219]

Answer:

is equal to the total number of products

Explanation:

3 0

3 years ago