Ask question

Ask question

All categories

2 years ago

13

WHO EVER CAN ANSWER THESE FOR ME I WILL MARK YO THE BRANLEIST!!!

2 answers:

pochemuha2 years ago

5 0

Answer:

4: 5times

5: 5^7

9: x^185

10: 4 times

Step-by-step explanation:

abruzzese [7]2 years ago

3 0

Answer:

Exercise 4: 15 times

Exercise 5: 5^10

Exercise 9: x^185

Exercise 10: n times

You might be interested in

A can of tennis balls costs $6. The total cost c of n cans, including sales tax t, is given by the equation c = 6n + t. Which is

lora16 [44]

Answer:

The reason why c = 6n + t is the same as c - t = 6n is because c is the sum of the addition problem. 6n and t are the addends. The inverse operation for addition is subtraction. c is the cost that will be reduced by t. The answer is still 6n.

3 0

3 years ago

646 is 85% of what number?

Lilit [14]

Let the number be y

The statement can be interpreted as

85% of y = 646

$\begin{gathered} \text{ }\frac{85}{100}\text{ x y = 646} \\ 85y\text{ = 64600} \\ y=\frac{64600}{85} \\ y=760 \\ \text{ The number is 760} \end{gathered}$

8 0

10 months ago

Find the x- and y-intercepts of the graph of -6 + y = 20. State your answers as

Jobisdone [24]

Answer:

y=26 (no x ) the y int is 26 I believe

Step-by-step explanation:

8 0

2 years ago

Consider a Poisson distribution with μ = 6.

bearhunter [10]

Answer:

a) $P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b) f(2) = 0.04462

c) f(1) = 0.01487

d) $P(X \geq 2) = 0.93803$

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In this question:

$\mu = 6$

a. Write the appropriate Poisson probability function.

Considering $\mu = 6$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

b. Compute f (2).

This is P(X = 2). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

So f(2) = 0.04462

c. Compute f (1).

This is P(X = 1). So

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

So f(1) = 0.01487.

d. Compute P(x≥2)

This is:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2)$

$P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.00248$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.01487$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.04462$

Then

$P(X < 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.00248 + 0.01487 + 0.04462 = 0.06197$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.06197 = 0.93803$

So

$P(X \geq 2) = 0.93803$

5 0

2 years ago

After a special medicine is introduced into a petri dish full of bacteria, the number of bacteria remaining in the dish decrease

Crazy boy [7]

Answer:

0.17

Step-by-step explanation:

The function can be rewritten as ...

B(t) = 9300·((1/2)^6)^t = 9300·(1/2)^(6t)

In order to multiply the number of bacteria by 1/2, the value of the exponent 6t must be equal to 1:

6t = 1

t = 1/6 ≈ 0.166667 ≈ 0.17

The culture loses half its size every 0.17 seconds.

7 0

3 years ago