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Alik [6]
2 years ago
13

WHO EVER CAN ANSWER THESE FOR ME I WILL MARK YO THE BRANLEIST!!!

Mathematics
2 answers:
pochemuha2 years ago
5 0

Answer:

4: 5times

5: 5^7

9: x^185

10: 4 times

Step-by-step explanation:

abruzzese [7]2 years ago
3 0

Answer:

Exercise 4: 15 times

Exercise 5: 5^10

Exercise 9: x^185

Exercise 10: n times

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Ann [662]
A phase shift is defined as the a<span>mount of x by which sinusoid is shifted to the left or right.
 
And yes, </span><span>every sine function be expressed as a phase shifted cosine function:
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sin(t)=cos(90-t)

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
4 0
2 years ago
Factors of polynomial 3xsquare +x-4
Dennis_Churaev [7]

Answer:

(3x + 4)(x - 1)

Step-by-step explanation:

3x^2 + x - 4

use middle term break method

we need two number which gives 12 when multiplied and 1 when subtracted

3x^2 + (4 - 3)x - 4

3x^2 + 4x - 3x - 4

x(3x + 4) -1(3x + 4)

(3x + 4)(x - 1)

4 0
2 years ago
Read 2 more answers
Jim bought the game system on sale for $195. Kaylen bought the same system at full price for $250. How much was the sale when ji
Arisa [49]
The sale was 55$ because if you subtract those you get 55 which is the difference between the two
3 0
2 years ago
Think about a number line. The integer 3 is 3 units from 0 on the number line. Which integer is also 3 units from 0 on the numbe
disa [49]
-3 is also three units from zero
4 0
2 years ago
In a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer
stira [4]

Answer:

We conclude that 80% of patients stop smoking when given sustained care.

Step-by-step explanation:

We are given that in a program designed to help patients stop smoking. 192 patients were given to sustained care, and 80.2% of them were no longer smoking after one month.

Let p = <u><em>percentage of patients stop smoking when given sustained care.</em></u>

So, Null Hypothesis, H_0 : p = 80%     {means that 80% of patients stop smoking when given sustained care}

Alternate Hypothesis, H_A : p \neq 80%     {means that different from 80% of patients stop smoking when given sustained care}

The test statistics that would be used here <u>One-sample z test for proportions</u>;

                        T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of patients who stop smoking when given sustained care = 80.2%

           n = sample of patients = 192

So, <u><em>the test statistics</em></u>  =  \frac{0.802-0.80}{\sqrt{\frac{0.802(1-0.802)}{192} } }

                                     =  0.07

The value of z test statistics is 0.07.

<u></u>

<u>Also, P-value of the test statistics is given by the following formula;</u>

                P-value = P(Z > 0.07) = 1 - P(Z \leq 0.07)

                              = 1 - 0.52790 = 0.4721

<u>Now, at 0.05 significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.</u>

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that 80% of patients stop smoking when given sustained care.

8 0
3 years ago
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