<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
The expression can be solved by expanding the bracket and multiplying out the terms
Therefore, the expression can be simplified as;
Alternatively, using the theorem of difference of two squares, which is
Hence,
Answer:
A and B
Step-by-step explanation:
Parallel lines are lines which have the same slope. Perpendicular lines have negative reciprocal slopes.
For the options:
A. Both equations have 7/5 as the slope. They are parallel.
B. The slopes are 1 and -1. These are perpendicular.
C. The slopes are 9/2 and are parallel.
D. The slopes are 7/3 and -3/7. They are perpendicular.
The solution is A and B.
Answer:
Step-by-step explanation:
It is the 2nd one and 4th one. The x intercepts are -1 and -3, so the factors are x + 3 and x + 1. The 4th choice is the actual equation and the 2nd is the factors
Answer 10000103984
Step-by-step explanation:
