9514 1404 393
Answer:
see attached
Step-by-step explanation:
The equation can be written in slope-intercept form as ...
y > -3x +4
The dashed boundary line has a y-intercept of (0, 4) and a slope of -3. Shading is where x-values and y-values are greater than those on the boundary line, so will be to the right and above the line.
Answer:
e. It will take 11 seconds to reach the maximum height of 1,936 feet.
f. It will take 22 seconds to return to the earth.
Step-by-step explanation:
Given:
Initial velocity = 352 ft/sec
Solving for question e.
To find the time required to reach the maximum height we will use the formula,
,
where is the starting velocity
is the initial height.
Using the velocity and starting height from our problem we have,
,
The path of this rocket will be a downward facing parabola, so there will be a maximum.
This maximum will be at the vertex of the graph.
To find the vertex we start out with which in our case is,
So, It will take 11 seconds for the rocket to reach its maximum height.
We will find maximum height using the formula by substituting value of t we get,
Hence the maximum height will be
Now Solving for question f.
To find the time required for rocket to reach earth.
We will set our formula to 0 to find the time.
Using the zero product property, we know that either -16t = 0 or t - 22 = 0. When -16t = 0 is at t = 0, when the rocket is launched. t - 22 = 0 gives us an answer of t = 22.
So the rocket reaches the Earth again at 22 seconds.