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amm1812
3 years ago
9

From 82 books to 138 books Find the percent increase. Round to the nearest percent.

Mathematics
1 answer:
FrozenT [24]3 years ago
3 0

Answer:

68%

Step-by-step explanation:

Calculate percentage change

from V1 = 82 to V2 = 138

(V2−V1)|V1|×100

=(138−82)|82|×100

=5682×100

=0.682927×100

=68.2927%change

=68.2927%increase

=68%

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Hey, could anyone help with this?
kumpel [21]

Answer:

The Answer is choice B, (-1,3)

Step-by-step explanation:

The solution to systems of linear equations is the point of intersection of the two lines. In this graph, the two lines cross where the x coordinate is -1 and the y-coordinate is 3

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3 years ago
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In your biology class, your final grade is based on several things: a lab score, scores on two major tests, and your score on th
ddd [48]

Answer:

the weighted score is 82.03

Step-by-step explanation:

The computation of the weighted score is as follows

= Respective scores × respective test or exam and score

= 0.21 × 90 + 0.24 × 71 + 0.24 × 71 + 0.31 × 79

= 18.9 + 21.6 + 17.04 + 24.49

= 82.03

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We simply applied the above formula so that the weighted score could be come

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3 years ago
Evaluate c-2 when c=7
Luba_88 [7]
5 is the answer. Hope this helps.
8 0
3 years ago
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Use the Factor Theorem and synthetic division to show x + 5 is a factor of f(x) = 2x3 + 7x2 − 14x + 5
olga2289 [7]

Answer:

Factor theorem: f(-5) = 0.

Synthetic division: f(x) = (x + 5)\, (2\, x^2 -3\, x + 1).

Step-by-step explanation:

<h3>Factor Theorem</h3>

By the factor theorem, a monomial of the form (x - a) (where a is a constant) is a factor of polynomial f(x) if and only if f(a) = 0.

In this question, the monomial is (x + 5), which is equivalently (x - (-5)). a = -5.

\begin{aligned}& f(-5) \\ &= 2 \times (-5)^{3} + 7 \times (-5)^{2}- 14\times (-5) + 5\\ &= -250 + 175 + 70 + 5 \\ &= 0\end{aligned}.

Hence, by the factor theorem,  (x + 5), which is equivalent to (x - (-5)), is a factor of f(x).

<h3>Synthetic Division</h3>

\begin{aligned}& f(x) \\ &= 2\, x^{3} + 7\, x^{2} - 14\, x + 5 \\ &= \underbrace{(x + 5) \, (2\, x^2)}_{2\, x^{3} + 10\, x^{2}} - 3\, x^{2} - 14\, x + 5 \\ &= \underbrace{(x + 5) \, (2\, x^2)}_{2\, x^{3} + 10\, x^{2}} + \underbrace{(x + 5)\, (-3\, x)}_{-3\, x^{2} - 15\, x} + (x + 5) \\ &= (x + 5)\, (2\, x^{2} - 3\, x + 1)\end{aligned}.

The remainder is 0 when dividing f(x) by (x + 5). Hence, (x + 5)\! is a factor of f(x)\!.

6 0
3 years ago
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