<u>Given</u>:
The equation of the circle is 
We need to determine the center and radius of the circle.
<u>Center</u>:
The general form of the equation of the circle is 
where (h,k) is the center of the circle and r is the radius.
Let us compare the general form of the equation of the circle with the given equation
to determine the center.
The given equation can be written as,

Comparing the two equations, we get;
(h,k) = (0,-4)
Therefore, the center of the circle is (0,-4)
<u>Radius:</u>
Let us compare the general form of the equation of the circle with the given equation
to determine the radius.
Hence, the given equation can be written as,

Comparing the two equation, we get;


Thus, the radius of the circle is 8
Answer:
x≤-3 1/2 or x>1
Step-by-step explanation:
The way we solve this is we simply rearrange the equation using algebra.
Step 1) For the first inequality, subtract 1/2 from both sides. This gets x by itself and turns the RHS into -3 1/2.
Step 2) For the second, add 3 to both sides. Once again, x is by itself, and the RHS is equal to 1.
Remark
This really can't be done unless you know that T is the midpoint. I'm pretty sure it is intended to be.
Solve
5x + 3 = 48 Subtract 3
5x = 48 - 3
5x = 45 Divide by 5
x = 45/5
x = 9