Question

Find p(0),p(1),p(-1) and p(2) of the 3x(x-2) ​

Answer 1

Answer:

make x→0

$p(0)=(0)^{2}-3(0)+2$

→ $p(0)=0+0+2$

→$p(0)=2$

$------$

Replace x→-1

$p(-1)=(-1) ^{2} -3 (-1)+2$

→ $p(-1)=1-3+2$

→ $p(-1)=0$

$----------$

Now make x→2

$p(2)=(2) ^{2} -3(2)+2$

→ $p(2)=4-6+2$

→ $p(2)=0$

$Answer:-2,0,0$

$-----------$

hope it helps...

have a great day!!