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ss7ja [257]
3 years ago
14

Find p(0),p(1),p(-1) and p(2) of the 3x(x-2) ​

Mathematics
1 answer:
Effectus [21]3 years ago
5 0

Answer:

<u>make x→0</u>

p(0)=(0)^{2}-3(0)+2

→ p(0)=0+0+2

→p(0)=2

------

<u>Replace x→-1</u>

p(-1)=(-1) ^{2} -3 (-1)+2

→ p(-1)=1-3+2

→ p(-1)=0

----------

<u>Now make x→2</u>

p(2)=(2) ^{2} -3(2)+2

→ p(2)=4-6+2

→ p(2)=0

Answer:-2,0,0

-----------

hope it helps...

have a great day!!

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