Answer:
The ordered pair is 
Step-by-step explanation:
I believe it doesnt exist because every one # on the left doesnt have a different # on the right..
Answer:
Area of first shape is 288
, area of second shape is 45
, area of third shape is 34
.
Step-by-step explanation:
Area of first shape
A=bh
A=18*16
A=288
Second shape
A=bh
A=9*5
A=45
Third shape
A= 1/2 h(b1+b2)
A=1/24(12+5)
A=1/2*4(12+5)
A=1/2*4(17)
A=1/2*68
A=34
Hello!
To solve algebraic equations, we need to use SADMEP. SADMEP is an acronym used only solve for x in algebraic equations. SADMEP is expanded to be: subtraction, addition, division, multiplication, exponents, and parentheses.
(a) 4 + 2(-1) = 10 + 2 (multiply)
4 + -2 = 10 + 2 (add)
2 = 12
This equation has no solutions because <u>2 is never equal to 12</u>.
(b) 30 = 10 - (6 + 10) (simplify the parentheses)
30 = 10 + -1(16) (multiply)
30 = 10 - 16 (simplify)
30 = -6
This equation has no solutions because<u> 30 and -6 is never equal to each other</u>.
(c) 8x = 4x + 4x + 10(x - x)
8x = 4x + 4x + 10(x - x) (simplify [add and subtract])
8x = 8x + 10(0) (multiply)
8x = 8x
This equation has an infinite number of solutions because if you <u>substitute any value into the original equation</u>, <u>both sides of the equation</u> will be <u>always equal</u>.
Answer: 3∛2
<u>Step-by-step explanation:</u>
First, factor 128 .... you need three common factors to bring one on the outside of the radical.
![\dfrac{3}{4}\sqrt[3]{128} \\\\\\=\dfrac{3}{4}\sqrt[3]{4\cdot 4\cdot 4\cdot 2} \\\\\\=\dfrac{3}{4}\cdot 4\sqrt[3]{2} \\\\\\=\large\boxed{3\sqrt[3]{2} }](https://tex.z-dn.net/?f=%5Cdfrac%7B3%7D%7B4%7D%5Csqrt%5B3%5D%7B128%7D%20%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B3%7D%7B4%7D%5Csqrt%5B3%5D%7B4%5Ccdot%204%5Ccdot%204%5Ccdot%202%7D%20%5C%5C%5C%5C%5C%5C%3D%5Cdfrac%7B3%7D%7B4%7D%5Ccdot%204%5Csqrt%5B3%5D%7B2%7D%20%5C%5C%5C%5C%5C%5C%3D%5Clarge%5Cboxed%7B3%5Csqrt%5B3%5D%7B2%7D%20%7D)
