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myrzilka [38]
3 years ago
9

Giulio holds a bag of 70 marbles in his hands. Jim blindfolds Giulio and keeps adding marbles to Giulio's bag, one at a time. Ho

wever, Giulio notices the difference in the weight only after Jim has added 5 marbles. They now repeat the same experiment with a bag of 140 marbles. This time, Giulio notices the difference in the weight only after Jim has added 10 marbles. This scenario BEST illustrates:
Mathematics
1 answer:
deff fn [24]3 years ago
8 0

Answer:

Weber's Law

Step-by-step explanation:

  • Weber's law States that it is a mathematical model of the difference threshold stating that the magnitude needed to detect a physical change in a stimulus is proportional to the absolute magnitude of that stimulus. Thus, the more intense the stimulus, the greater the change that must be made in it to be noticed.
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ILL GIVE YOU BRAINLIST !!!
Alecsey [184]

Answer:

-\frac{15}{16}

Step-by-step explanation:

\frac{1}{4} ^{2}= \frac{1}{16}

2*(pq)= 2(\frac{1}{6})= \frac{1}{3}

-3q^{2}= -3(\frac{4}{9} )= -\frac{4}{3}

\frac{1}{16} +\frac{1}{3}-\frac{4}{3}=

\frac{1}{16} -1=

-\frac{15}{16}

4 0
3 years ago
Three friends went to the movies. Each movie ticket cost $8.50. Each person ordered a drink for $4.75. Two friends also bought p
vfiekz [6]

Answer:

P = $7.00

Step-by-step explanation:

Movie tickets = $8.50

Drink = $4.75

Two friends also bought popcorn

Total spent by the group = $53.75

Given equation:

3(8.50 + 4.75) + 2p = 53.75

Where,

P = cost of one order of popcorn

3(8.50 + 4.75) + 2p = 53.75

25.50 + 14.25 + 2p = 53.75

39.75 + 2p = 53.75

2p = 53.75 - 39.75

2p = 14

p = 14 / 2

p = 7

p = $7.00

8 0
3 years ago
Marine scientists categorize signature whistles of bottlenose dolphins by typelong dash—type ​a, type​ b, type​ c, etc. In one s
r-ruslan [8.4K]

Answer:

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 185, \pi = \frac{100}{185} = 0.5405

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 - 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.4687

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 + 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.6123

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

3 0
3 years ago
Three times the largest of three consecutive even integers is 76 more than the sum of the other two integers what are the intege
DerKrebs [107]
<span>go tot he website of 
</span>
https://www.algebra.com/algebra/homework/Problems-with-consecutive-odd-even-integers/Problems-with-c...

It will help you understand the problem and give you the answer.
7 0
3 years ago
Find the 17th term of the arithmetic sequence -5, 1, 7, 13, ... *
xz_007 [3.2K]

Answer:

91

Step-by-step explanation:-5, 1, 7, 13

the common diference is : d = ( 13)-(7)=(7)-(1)=(1)-(-5)=6

the firt term is A1 = -5

the n-ieme term is : An = A1 +(n-1)d

An = -5+6(n-1)

An = 6n-11

the 17th term in the arithmetic sequence  is : A17 = 6(17)-11 =91

Read more on Brainly.com - brainly.com/question/15374982#readmore

7 0
3 years ago
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