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3 years ago

6

PLS HELP ME ASAP WITH THIS WHOLE PAGE! THANK YOU SOO MUCH!!

1 answer:

Doss [256]3 years ago

6 0

1a) The function has arrows on both ends and no place in the middle where it is not defined. Its domain is ...
All Reals

1b) The function gives no output values below -3, but it gives output values of -3 and all above that. Its range is ...
y ≥ -3

1c) For values of x less than -1, the function's output is 1. This matches g(x) and s(x). At x=0, the function's output is -3, which only matches g(x). The appropriate choice is ...
g(x)

2b) The function is only defined for 0 ≤ x < 8. This is its domain.

3) A definition might be ...
$y=\left\{ \begin{array}{rcl}x+1 & \mbox{for} & -4\le x \le 1\\-x & \mbox{for} & 1 < x \le 3 \end{array}$

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Given: m∠A = m∠C = 90° AB ║ DC Prove: ∆ABD ≅ ∆CBD

Genrish500 [490]

Answer:

Angle-Angle-Side (AAS)

Step-by-step explanation:

Given triangles; ΔABD and ΔCBD

<A = <C = $90^{0}$ (right angle property)

AB ║ DC (given)

Then,

DA ║ CB

<B ≅ <D (congruent property)

DB ≅ BD (similarity property)

<D + <B = <B + <D (complementary angles, and property of triangles)

Therefore by Angle-Angle-Side (AAS),

∆ABD ≅ ∆CBD

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