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3 years ago

What is the domain of the function y=2 square root x-6

Mathematics

1 answer:

beks73 [17]3 years ago

5 0

Answer:

6 ≤ x < ∞

Step-by-step explanation:

interval notation: [6, ∞)

set builder notation: {x|x ≥ 6}

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Please help! I will give 50 points and brainliest.

QveST [7]

Answer:

Step-by-step explanation:

f * g = (x^2 + 3x - 4) (x+4)

open bracket

x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)

x³ +3x²-4x+x²+12x-16

x³+3x²+x²-4x+12x-16

x³+4x²+8x-16 (domain is all real numbers.

f/g = (x^2 + 3x - 4)/(x+4)

factorising (x^2 + 3x - 4)

x²+4x-x_4

x(x+4) -1 (x+4)

(x+4)(x-1)

f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)

Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.

Hence I got x - 1, and x cannot equal -4

So the domain is just all real numbers without -4

8 0

3 years ago

Find the length x to the nearest whole number. A right triangle has a vertical leg of length x units, a base leg with a length o

wel

Complete Question

The diagram for this question is shown on the first uploaded image

Answer:

The value of x is $x = 274 \ unites$

Step-by-step explanation:

From the question we are told that

The length of the vertical length is $x$

The length of the base leg is L = 330 + d units

The length of the bisecting line segment is h

The base angle is $\theta = 28^o$

The angle between d and line segment is $\theta_1 = 56^o$

For the first angle

$Tan \theta_1 = \frac{x}{d}$

=> $d = \frac{x}{Tan \theta _1}$

For the whole big triangle

$Tan \theta = \frac{x}{330 + d}$

=> $d = \frac{x}{Tan \theta } -330$

So equating the both d

$\frac{x}{Tan \theta _1} = \frac{x}{Tan \theta } -330$

Substitute values

$\frac{x}{Tan (56)} = \frac{x}{Tan (28) } -330$

$0.6745 x = 1.880x -330$

$1.20549 x = 330$

$x = 274 \ unites$

5 0

3 years ago

Can someone please help me im being timed ‼️

Ad libitum [116K]

125 because it’s symmetrical between both

3 0

2 years ago

Read 2 more answers

20 PTS LOOK AT PIC FOR QUESTION WILL MARK BRAINILEST

hjlf

Answer:

263.25 cm

Step-by-step explanation:

5 0

3 years ago

Area of square= 625 m sq Perimeter =??

sveticcg [70]

Answer:

100 m

Step-by-step explanation:

Given :

Area of square = 625 m²

#1) Finding the side length

Area = (side length)²
⇒ side length = √Area
⇒ side length = √625
⇒ side length = 25 m

#2) Calculating perimeter

Perimeter = Total length of the sides of the shape
Perimeter = 4 x side length [a square has 4 equal sides]
⇒ Perimeter = 4 x 25
⇒ Perimeter = 100 m

5 0

2 years ago

Read 2 more answers