Answer:
x value of vertical asymptote and y value of horizontal asymptote
Step-by-step explanation:
The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)
As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)
Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?
When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5
What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0
What y value does g(x) approach as x gets bigger? Well, as x gets big, 1/(x-5) gets small, approaching 0. The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote
Answer:
55
Step-by-step explanation:
(after the first "1") You need to add the previous two numbers together to get the next number in the pattern.
7
You divide 28 by 4 and get 7. Then you divide 49 by whatever you get.
So we can take the volume of a cube formula and set it equal to the volume that we actually know: 64 centimeters cubed. So in order to find the length of the edge, which is a side, we need to cube root both sides of this equation. On the left-hand side, the cube root cancels all the cube.