Answer:
Step-by-step explanation:
14. You would add 41 + 41 + 61 + 61 because you just need to add together all the sides.
15. you need to measure the all the sides for 15 and do the same thing that you did on 14
42.52 g
im pretty sure this is the answer
You just have to figure it where you can place 2 solid lines and get 10 triangles ( i can only get 9). Think about the pentagon in the middle of the triangles and see if somehow you can create more triangles using only the two straight lines.
The second-degree polynomial function f(x) that has a lead coefficient of 4 and roots 5 and 2 is f(x) = 4x² -28x + 40. The correct option is the last option f(x)=4x²-28x+40
<h3>Quadratic equation</h3>
From the question, we are to determine which second-degree polynomial function f(x) has a lead coefficient of 4 and roots 5 and 2
To determine this, we will use the given roots to determine the equation
The roots are 5 and 2
Thus
x = 5 and x = 2
x - 5 = 0 and x - 2 = 0
Therefore,
(x -5)(x -2) = 0
Distributing
x(x -2) -5(x -2) = 0
x² -2x -5x + 10 = 0
x² -7x + 10 = 0
Now, multiplying through by 4, we get
4x² -28x + 40 = 0
Thus, the function becomes f(x) = 4x² -28x + 40
Hence, the second-degree polynomial function f(x) that has a lead coefficient of 4 and roots 5 and 2 is f(x) = 4x² -28x + 40. The correct option is the last option f(x)=4x²-28x+40
Learn more on Quadratic Equation here: brainly.com/question/19257086
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