To get 17, you could do 20-3.
To get 41, you could do 50-9.
And to get 71, you could do 80-9.
Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
175% of 14.2 is saying that
1.75(14.2)=24.9
Any questions please just ask. Thank you.
Answer:
<u>Direct Variation is a relation that is of the form y = mx.</u>
and
<u>Partial Variation is a relation that is of the form y=mx+b</u>
Explanation:
This is a simple way to see the difference between them.
<em>Hope This help you!</em>
-π/2 < arctan(x) < π/2
So cos(π/2) < cos(arctan(x)) < cos(0)
0 < cos(arctan(x)) < 1
