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tatuchka [14]
3 years ago
13

Identify any constraints on the domain

Mathematics
1 answer:
slega [8]3 years ago
8 0

Answer:

Step-by-step explanation:

A vertical asymptote represents a value at which a rational function is undefined, so that value is not in the domain of the function. A reciprocal function cannot have values in its domain that cause the denominator to equal zero. In general, to find the domain of a rational function, we need to determine which inputs would cause division by zero.

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Name a point that is 20 units away from (5,-2)​
Fudgin [204]

Answer:

Distance between both points is 20units.

Applying the Distance between Points Formula

d= √(y₂-y₁)²+(x₂-x₁)²

x₁= 5 y₁=–2

x₂= ? y₂= ?

20 = √ [y -(-2)]² + (x - 5)²

Taking the square of both sides to eliminate the square root on the right.

20² = ( y + 2)² + (x - 5)²

400 = y² + 4y + 4 + x² – 10x + 25.

400 = x² + y² – 10x + 4y + 29.

x² + y² – 10x + 4y = 400 – 29

x² + y² – 10x + 4y = 371--------------eqn 1.

We called that eqn 1 cause we need another equation to solve this.

To solve an Equation with 2 variables... You need 2 equation.

To solve that of 3 variables.... you need 3 equations(Basic Math Rules).

We're dealing with 2 variables in this case(x, y).

Now

We'd need to think in order to create another equation that'll satisfy the distance or point.

We know that the distance between both Points(known and unknown) is 20.

Half that distance is 10.

The distance of 10 will occur at the center of these 2 points.

So lets apply the formula for Mid point to get the coordinate of the center.

Midpoint

let p be the x position and q be the y position of the midpoint

p = (x₁ + x₂)/2. q = (y₁ + y₂)/2

Starting from the know point (5 , -2)

x₁=5 y₁=–2

p = (5 + x)/2. q = (–2 + y)/2

p = (x + 5)/2 q = (y–2)/2.

This is the coordinate of the Midpoint.

Now We know that the distance between (5, -2) and [(x + 5)/2 , (y–2)/2] is 10(midpoint).

Applying the distance between points again.

d = √(y₂ - y₁)² + (x₂ - x₁)²

x₁= 5 y₁= -2

x₂= (x + 5)/2 y₂= (y–2)/2

10 = √[(y–2)/2 -(-2)]² + [ (x+5)/2 – 5)]²

10 = √[(y–2)/2 + 2]² + [(x+5)/2 – 5)]²

Squaring both sides to remove square root on the right and also Taking the LCM in each bracket

We have

10² = [ (y + 2)/2]² + [ (x–5)/2]²

Distributing the "2" on the denominator to each individual number in the parentheses.

100 = (y/2 + 1)² + (x/2 – 5/2)²

100 = y²/4 + y + 1 + x²/4 –5x/2 + 25/4.

Multiply through by 4 to clear fractions.

400 = y² + 4y + 4 + x² – 10x + 25

Rearranging

x² + y² – 10x + 4y = 371.

Hmm...

Equation 1 and 2 Are the Same.

Something is Wrong!

Pls Recheck the Question

I do believe that One value of the unknown point should be given.

I maybe be wrong somewhere else too.

Pls correct in the comment section if you spot it.

7 0
3 years ago
A rectangular prism is completely packed with 54 cubes of edge length fraction 1 over 2 inch, without any gap or overlap. Which
Paha777 [63]
54/8 = 6 6/8 . . . . . the 1st selection is appropriate
7 0
3 years ago
What are the roots of 2x^2+4x+7? Use the quadratic formula. Show your work
attashe74 [19]

Answer:

First you must rewrite the given equation in standard form:

2x^2 - 4x + 7 = 0.  Here a=2, b=-4 and c=7.

The solutions are thus 

      -[-4] plus or minus sqrt( [-4]^2 - 4[2][7] )

x = --------------------------------------------------------

                                  4

                  4 plus or minus sqrt (16 - 56)

or:     x = --------------------------------------------

                                       4

16-56 = - 40, a negative number.  Thus, we must introduce the imaginary operator:  sqrt (-40) = 2i*sqrt(10)

The roots are thus:

        4 plus or minus 2i sqrt(10)              2 plus or minus i*sqrt(10)

x = -----------------------------------------  =  ---------------------------------------

                           4                                                        2

3 0
3 years ago
Find a rational number between and 9/10 and 1<br>​
Lapatulllka [165]

Answer:

1 is the answer

Step-by-step explanation:

5 0
3 years ago
PLS HELP REALLY NEED THIS
Pie
I wanna know if it will let me post the answer bc it literally won’t

3 0
3 years ago
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