(1) R+G+B=50
(2) R=B+6
(3) G=B-4 so substitute G in (1)
R+B-4+B=50 substitute (2) in here
B+6+B-4+B=50 group like terms and solve
3B+2=50
3B=50-2
B=48/3=16 substitute in (2) and (3)
R=16+6=22
G=16-4=12
Check
22+12+16=50✅
the second and the last,
since quadratic inside radical without multiplication with linear function
Answer:
x = 25.6
Step-by-step explanation:
As we can see, this is a right triangle, so there are known relationships
well to start we have to know the relationship between angles, legs and the hypotenuse
α = 43
a: adjacent = x
o: opposite
h: hypotenuse = 35
sin α = o/h
cos α = a/h
tan α = o/a
we see that it has (angle, adjacent, hypotenuse)
cos α = a/h
cos 43° = x / 35
cos 43° * 35 = x
25.59 = x
if we want to round to the nearest tenth
x = 25.59 = 25.6
10% of 4200 is 420
2% of 4200 is 84
420+84 is 504
4200-504=3696
Hope this helps
