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ipn [44]
4 years ago
9

2/x=1/4 help me solve this

Mathematics
2 answers:
bonufazy [111]4 years ago
8 0
It is a linear equation with only one unknown, although it looks strange because of the fractions, so lets get rid of the fractions:
<span>2/x = 1/4
</span>(2/x) = (<span>1/4)
</span>4*(2/x) = <span>1
8/x = 1
8 = 1*x
x = 8
that is the solution</span>
lord [1]4 years ago
6 0
/ mean division so you would take 2 divided by 8 to get 1/4
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Find Four Numbers that form a geometric progression such that the second term is less than the first by 35, and the third term i
Olegator [25]

Answer:

  • -35/3, -140/3, - 560/3, -2240/3
  • 7, -28, 112, - 448  

Step-by-step explanation:

<u>The terms are:</u>

  • a₁, a₂, a₃, a₄

<u>Given:</u>

  • a₁ = a₂ + 35
  • a₃ = a₄ + 560

<u>Use the nth term formula:</u>

  • a₂ = a₁r
  • a₃ = a₁r²
  • a₄ = a₁r³

<u>Substitute:</u>

  • a₁ = a₁r + 35 ⇒ a₁(1 - r) = 35
  • a₁r² = a₁r³ + 560  ⇒ a₁(1 - r)r² = 560

<u>Divide the second equation by the first:</u>

  • r² = 560/35
  • r² = 16
  • r = √16
  • r = ± 4

<u>Use the first equation to find the first term:</u>

  • a₁( 1 ± 4) = 35
  • 1. a₁ = 35/-3 = -35/3
  • 2. a₁ = 35/5 = 7

<u>We have two sequences:</u>

r = 4

  • -35/3, -140/3, - 560/3, -2240/3

r = -4

  • 7, -28, 112, - 448  
8 0
3 years ago
Determine the solution set of x2 - 80 = 0
meriva

                                         x²  -  80  =  0
Add 80
to each side:                      x²          =  80

Square root
each side:                         x            =  √80

Look it up:                        x  =  + 8.944... (rounded)
                                 and
                                       x  =  - 8.944...  (rounded).
___________________________________

Here's a cleaner solution:

                                         x²  -  80  =  0
Add 80
to each side:                      x²          =  80

Square root
each side:                         x            =  √80

 But  80 = 16 · 5

 So     √80  =  √16 · √5

            √16 = 4, so            x  = 4 √5      

 

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