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4 years ago

2/x=1/4 help me solve this

2 answers:

8 0

It is a linear equation with only one unknown, although it looks strange because of the fractions, so lets get rid of the fractions:
2/x = 1/4
(2/x) = (1/4)
4*(2/x) = 1
8/x = 1
8 = 1*x
x = 8
that is the solution

lord [1]4 years ago

6 0

/ mean division so you would take 2 divided by 8 to get 1/4

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3 years ago

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3 years ago

Read 2 more answers

Aya = a1 + (n - 1)d

Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

Step-by-step explanation:

Given

a₁ = -33

d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

substituting a₁ = -33 and d = 4 in the nth term of the sequence

$a_n=-33+\left(n-1\right)4$

$\:a_n=-33+4n-4$

$a_n=4n-37$

Thus, the nth term of the sequence is:

$a_n=4n-37$

now substituting n = 26 in the nth term to determine the 26th term of the sequence

$a_n=4n-37$

$a_{26}=4\left(26\right)-37$

$a_{26}=104-37$

$a_{26}=67$

Therefore, the 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

7 0

3 years ago

A jar contains 8 pennies, 5 nickels and 7 dimes. A child selects 2 coins at random without replacement from the jar. Let X repre

Akimi4 [234]

Answer:

a. The probability x = 2 cents = 7/22

b. The probability x = 6 cents = 35/66

c. The probability x = 10 cents = 5/33

d. The probability x = 11 cents= 28/33

e. The probability x = 15 cents = 20/33

f. The probability x = 20 cents = 14/33

g. The expected value of x = 5.9

Step-by-step explanation:

This is a binomial probability distribution. The number of trials is known .

a. The probability x = 2 cents.

Probability ( X=2) P( selecting 2 dimes)= 7C2 / 12c2

= 21 / 66 = 7/22

b. The probability x = 6 cents.

Probability ( X=6) P( selecting a nickel and a dime)= 5C1 * 7C1/ 12c2

= 5*7 / 66 = 35/66

c. The probability x = 10 cents.

Probability ( X=10) P( selecting two nickels )= 5C2 / 12c2)

= 10/ 66 = 5/33

d. The probability x = 11 cents.

Probability ( X=11) P( selecting a penny and a dime)= 8C1 * 7C1/ 12c2)

= 8*7 / 66 = 56/66= 28/33

e. The probability x = 15 cents.

Probability ( X=15) P( selecting a penny and a nickel)= 8C1 * 5C1/ 12c2)

= 8*5 / 66 = 40/66= 20/33

f. The probability x = 20 cents.

Probability ( X=20) P( selecting 2 pennies )= 8C2 / 12c2)

= 28 / 66 = 14/33

g. The expected value of x.

E(X) = np

E(X) = 2 * (8C2+ 5C2+ 7C2)/(8+5+7) = 2( 28+10+21)/20

=2(59)/20= 5.9

8 0

3 years ago