Answer:
A). 15
B). -1.2
Step-by-step explanation:
A). [10(x+3)]-20 = 160
10x+30-20 = 160
10x+10 = 160
10x = 160-10
10x = 150
x = 150/10
x = 15
B). 5{[4(8+(5x))]-9} = 85
5(32+20x+9) = 85
5(32+9+20x) = 85
5(41+20x) = 85
205+100x = 85
100x = 85-205
100x = -120
100x/100 = -120/100
x = -1.2
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HOPE THIS HELPS!!!
The present age of mother and her daughter respectively are; 40 and 10 years respectively.
<h3>How to Solve Algebra Word Problems?</h3>
Let x and y be the present age of mother and her daughter respectively.
Therefore;
x + y = 50
x = 50 − y .....(1)
After 20 years, mother's age will be twice her daughter's age at the time. Thus;
x + 20 = 2(y + 20)
x − 2y = 20 .....(2)
Plugging eq 1 into eq 2 gives us;
50 − y − 2y = 20
3y = 30
y = 10
Thus;
x = 50 − 10
x = 40
Thus, the present age of mother and her daughter is 40 and 10 years respectively.
Translation of the question into English is;
The sum of the present ages of mother and her daughter is 50 years. After 20 years, mother's age will be twice her daughter's age at the time. Find their present ages.
Read more about Algebra Word Problems at; brainly.com/question/21405634
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Answer:
- The grade point average is 2.92
- The student didn't make the Dean's list because the student's GPA is less than 3.0
Step-by-step explanation:
- I take the grades as A,D,A,C,B not AA,DD,AA,CC,BB.
- I take numbers of credit hours as 4,2,2,3,1 not as 44, 22, 22, 33, and 11.
Since quality points to letter grades are A=4; B=3; C=2; D=1; F=0, weighted mean is the sum of the qulity points times corresponding credit hours divided by the total credit hours:
≈ 2.92
Since 2.92<3.0, the student is not in Dean's list.
13 x 12 = 156 square inches
Well, the affect would be 3x less on the area of the square
