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3 years ago

Can some help please?!?!

Mathematics

1 answer:

Alexandra [31]3 years ago

6 0

Answer:

<em>Choice D.</em>

Step-by-step explanation:

Vertical line test for functions:

If a vertical line drawn anywhere on the graph intersects the graph in more than one point, it is not a function.

If you draw a vertical line passing through any point between x = -4 and x = 4, the line will intersect two points on the circle. The relation fails the vertical line test. That shows that this relation is not a function.

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Determine the number of x-intercepts that appear on a graph of each function.

Ymorist [56]

3 x-intercepts:

1) x = -1
2) x = 3
3) x = 4

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3 years ago

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Solve 2x - 1 < 7 and 5x + 3 < 3. {x | x < 0} {x | x < 4} {x | 0 < x < 4}

nataly862011 [7]

2x -1 <7 ; then, 2x < 8; then x < 4;
5x + 3 < 3; then, 5x < 0; then x < 0;
Finally, {x / x < 0};

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Earth's radius is approximately 6400 km. What is the surface area & volume of the earth?

Tamiku [17]

Answer:

$SA=514,457,600\ km^{2}$

$V=1,097,509,546,667\ km^{3}$

Step-by-step explanation:

step 1

Find the surface area

we know that

the surface area of a sphere is equal to

$SA=4\pi r^{2}$

substitute

$SA=4 \pi (6,400)^{2}$

$SA=163,840,000 \pi\ km^{2}$

substitute the approximate value of pi (3.14)

$SA=(3.14) (163,840,000)$

$SA=514,457,600\ km^{2}$

step 2

Find the volume

The volume is equal to

$V=(4/3)\pi r^{3}$

substitute

$V=(4/3)(3.14) (6,400)^{3}$

$V=1,097,509,546,667\ km^{3}$

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3 years ago

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Please answer the question on the attachment <3

nika2105 [10]

Answer:

Step-by-step explanation:

hypotenuse (h) = 9.4

base(b) = 1.9

cos x = b/h

cos x = 1.9/9.4

x = cos ^-1 ( 1.9/9.4)

x = 78.3°

hope it will help :)

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3 years ago

Johan found that the equation –2|8 – x| – 6 = –12 had two possible solutions: x = 5 and x = –11. Which explains whether his solu

Effectus [21]

$-2|8-x|-6=-12 \ \ \ |\hbox{add 6} \\
-2|8-x|=-6 \ \ \ |\hbox{divide by (-2)} \\
|8-x|=3 \\
8-x=-3 \ \lor \ 8-x=3 \\
-x=-3-8 \ \lor \ -x=3-8 \\
-x=-11 \ \lor \ -x=-5 \\
x=11 \ \lor \ x=5 \\
\boxed{x=5 \hbox{ or } x=11}$

It should be x=11 instead of x=-11, so he is not correct because he made a sign error.

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3 years ago

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