Height of the water increasing is at rate of 
<h3>How to solve?</h3>
With related rates, we need a function to relate the 2 variables, in this case it is clearly volume and height. The formula is:
There is radius in the formula, but in this problem, radius is constant so it is not a variable. We can substitute the value in:
Since the rate in this problem is time related, we need to implicitly differentiate wrt (with respect to) time:
In the problem, we are given 
So we need to substitute this in:
Hence, Height of the water increasing is at rate of
<h3>Formula used: </h3>
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681,700,000 just like that six hunnit eight juan mill sebn hunnit thousand
He would have to work 24 weeks to get the same amount from each job.
<span>Diagonals of a rhombus are perpendicular and bisect each other. This means this rhombus is composed of four right triangles with legs of length 6 cm and 8 cm, with their hypotenuses forming the perimeter of the rhombus. The Pythagorean theorem a^2+ b^2 = c^2 can be used to find the length of the hypotenuse. 6^2+8^2 = 36+64 = 100. The square root of 100 is 10, so the length of a side of the rhombus is 10 cm.</span>
