Let w= the length of the side perpendicular to the barn
300-2w= length of the side parallel to the barn
A=w(300-2w)
A=-2w^2+300w
The formula for the w-value of maximum is:
=-b/2a
thus our value will be:
300/4
=75
and
300-2(75)
=150
thus the dimensions to maximize the area is 75 by 150
Answer:
Step-by-step explanation:
In ΔABC & ΔDCE
DE // AB Given
∠CDE ≅ ∠CAB Corresponding angles are congruent
∠CED ≅ ∠CBA Corresponding angles are congruent
ΔABC ~ Δ DEC AAA similarity
Answer:
sorry i dont know
Step-by-step explanation:
Answer:
They will need four gallons to be able to go 16 miles.
33.33? im not sure, but you do a/b=p/100. p is the percent, a is the part of the whole number, b. so the equation would be 20/b=60/100. then you do cross multiplication (60b=2000) then you divide.
