Answer:
Number of oxen = 16
Number of chickens = 6
Step-by-step explanation:
Let,
x be the number of oxen
y be the number of chickens
According to given statement;
x+y = 22 Eqn 1
4x + 2y = 76 Eqn 2
Multiplying Eqn 1 by 4
4(x+y=22)
4x+4y=88 Eqn 3
Subtracting Eqn 2 from Eqn 3
(4x+4y)-(4x+2y)=88-76
4x+4y-4x-2y = 12
2y = 12
Dividing both sides by 2
![\frac{2y}{2}=\frac{12}{2}\\y=6](https://tex.z-dn.net/?f=%5Cfrac%7B2y%7D%7B2%7D%3D%5Cfrac%7B12%7D%7B2%7D%5C%5Cy%3D6)
Putting y = 6 in Eqn 1
x + 6 = 22
x = 22 - 6
x = 16
Hence,
Number of oxen = 16
Number of chickens = 6
(X-4)*(X-2)=x^2-6x+8 so x=4,2
Answer:
Explanation:
You can find the theoretical probability of the event "the sum of the numbers is at least 4".
The theoretical probability is:
- number of positive outcomes / number of possible outcomes.
<u>1. Number of positive outcomes.</u>
The number of positive outcomes is the amount of ways for which the sum of the numbers is at least 4.
Those are:
- Sum = 4: (1,3); (2,2), (3,1) → 3 ways
- Sum = 5: (1,4), (2,3), (3,2), (4,1) → 4 ways
- Sum = 6: (1,5), (2, 4), (3, 3), (4, 2), (5,1) → 5 ways
- Sum = 7: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) → 6 ways
- Sum = 8: (2,6), (3,5), (4,4), (3,5), (2,6) → 5 ways
- Sum = 9: (3,6), (4,5), (5,4), (6,3) → 4 ways
- Sum = 10: (4,6), (5,5), (6,4) → 3 ways
- Sum = 11: (5, 6), (6,5) → 2 ways
Thus, the total number of ways to have a sum of at least 4 is: 3 + 4 + 5 + 6 + 5 + 4 + 3 + 2 + 1 = 33.
<u>2. Number of possible outcomes</u>
The total number of possible outcomes is found by multiplying the ways each die can be rolled, this is: 6 × 6 = 36.
<u>3. Probability</u>
Then, the searched probability is 33/36 = 11/12 ≈ 0.92
Answer:
Step-by-step explanation:
<u>Given</u>
<u>Solve for x</u>
- 2x = 7 - 3
- 2x = 4
- x = 4/2
- x = 2
Answer: 2/49
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