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Lostsunrise [7]
3 years ago
7

What is number 61 and a step by step explaination please?

Mathematics
1 answer:
astra-53 [7]3 years ago
3 0

1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3

Recall that m\log_b(n)=\log_b(n^m), so

ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3

Condense the left side by using sum and difference properties of logarithms:

\log_b(m)+\log_b(n)=\log_b(mn)

\log_b(m)-\log_b(n)=\log_b\left(\dfrac mn\right)

Then

ln(2/3 <em>x</em> ¹ʹ³) = 3

Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)

exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)

Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to

2/3 <em>x</em> ¹ʹ³ = exp(3)

Now solve for <em>x</em>. Multiply both sides by 3/2 :

3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)

<em>x</em> ¹ʹ³ = 3/2 exp(3)

Raise both sides to the power of 3:

(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³

<em>x</em> = 3³/2³ exp(3×3)

<em>x</em> = 27/8 exp(9)

which is the same as

<em>x</em> = 27/8 <em>e</em> ⁹

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Answer:

Step-by-step explanation:

You are to make 5 assemblies.

Each assembly requires the use of 1 Type A bolt.

To make the 5 assemblies, you need 5 Type A bolts.

The container of bolts has a total of 60 bolts.

The focus - Type A bolts - is 20 out of this 60.

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(A) What is the probability of taking the exact number of Type A bolts you need for your 5 assemblies, if you randomly take 10 bolts from the container?

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(B) What is the probability of taking/having less than 5 Type A bolts out of the randomly selected 10 bolts? The solution is to sum up the following:

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