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3 years ago

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Mathematics

1 answer:

Stels [109]3 years ago

8 0

Answer:

Hola no se chino.......

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ANSWER THE QUESTION FOR BRAINLIEST

Alex17521 [72]

The first one is the answer

5 0

2 years ago

Read 2 more answers

The diagram shows the net of a juice box. The box is a rectangular prism.

Hoochie [10]

Answer:

269.6 square centimeters

Step-by-step explanation:

The correct question is

The diagram shows the net of a juice box. the box is a rectangular prism. what is the surface area of the juice box? 6.4 cm 4 cm 10.5 cm

we know that

The surface area of a rectangular prism is equal to

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of the prism

we have

$L=6.4\ cm\\W=4\ cm\\H=10.5\ cm$

Find the area of the base B

$B=LW$

substitute the given values

$B=(6.4)(4)=25.6\ cm^2$

Find the perimeter of the base P

$P=2(L+W)$

substitute the given values

$P=2(6.4+4)=20.8\ cm$

Find the surface area

$SA=2B+PH$

substitute

$SA=2(25.6)+(20.8)10.5=269.6\ cm^2$

6 0

3 years ago

Assume Cylinder A and Cone B are the same height and the bases have the same radius. If A has a volume of 18π cm3, what is the v

disa [49]

Answer:

Option A $V_B=19\ cm^3$

Step-by-step explanation:

The volume of a cone is:

$V_B = \pi\frac{hr ^ 2}{3}$

The volume of a cylinder is:

$V_A = \pi(r ^ 2)h$

Both figures have the same height h and the same radius r.

The volume of the cylinder $V_A = 18\pi\ cm ^ 3$

We want to find the volume of the cone.

Then, we find r and h:

$V_A = 18\pi = \pi(r ^ 2)h$

We simplify.

$V_A = 18 = (r ^ 2)h$

Then the product of $(r ^ 2)h = 18$ .

We substitute this in the cone formula and get:

$V_B =\frac{\pi}{3}(18)\\\\V_B = \frac{18}{3}\pi\\\\V_B=19\ cm^3$

8 0

2 years ago

Read 2 more answers

How to simplify this

Afina-wow [57]

Hello,

the answer will be the last one
\

hope this help

4 0

3 years ago

Assigned newbits with the opposite values of oldbits if flipbits is true. ex: if oldbits = [1, 1, 0, 1] and flipbits is 1, then

Kisachek [45]

Franck's answer is better (using ~), but I just wanted to point out that the conditional in yours is slightly redundant. It's easy to forget that, since you already have a boolean value, you don't need to perform a comparison in your conditional. So you could have just done this...

if x x = false; else x = true; end

5 0

2 years ago